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3 years ago

The ordered pair (0,4) is a solution of what system?

Mathematics

2 answers:

igomit [66]3 years ago

7 0

I can think of one
(x,y) format
if x=0, y=4 so
y=x+4 is one equation

GenaCL600 [577]3 years ago

4 0

BBBHH JNKB,M.NBHGV VHBNJIHUY7IGTFVC FNVGHUYIJKM,

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For the write a story just make your own problem and answer it idk wut the the other one is

zavuch27 [327]

Answer:

1.) Alex and Jemma decided that they will separate the dozen doughnuts that they bought. Since Jemma loved doughnuts she got 7, and Alex got 5.

2.) 35:49

Divide 35 and 5.

35/5=7

Multiply 7 by 7.

7 x 7=49.

The missing side will be 35:49

4 0

4 years ago

In 1983, a can of house paint cost $16.35. In 2000, a can of house paint cost $28.94, and in 2005, a can of house paint cost $32

Readme [11.4K]

The Consumer Price Index is calculated through the equation,
CPI = (current period price/base period price) x 100
The base period is 1983. Solving the CPIs for 2000 and 2005
(2000)
CPI = ($28.94/$16.35) x 100 = 177
(2005)
CPI = ($32.54/$16.35) x 100 = 199
The difference between the CPIs of 2005 and 2000 is 199 - 177 = 22.

8 0

3 years ago

Read 2 more answers

An airplane is ascending at a constant rate of 15 feet per second what is the change in altitude during 10 minutes of flight

fenix001 [56]

Answer:

9000 ft

Step-by-step explanation:

Given: A airplane is ascending at a constant rate of 15 feet per second,

What we need to know: The change in altitude during 10 minutes of flight,

60 seconds = 1 minute

60 × 10

= 600 seconds

600 × 15

= 9000 ft

Therefore there was a 9000 ft change in altitude during the 10 minutes of the flight.

6 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago

DO NOT GUESS PLEASE!!

allochka39001 [22]

1. A
2. B
3. B
4. D=11
5. 25, 20,

By order of operations, the answer above which is marked brainliest is incorrect

6 0

4 years ago