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olga_2 [115]
3 years ago
15

Alison bought 12 cases for a party. She gave the cashier $30 and was given $3.24 in change. How much did Alison pay for one case

of water?
Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0
Alison payed 2.23 dollars money money cash cash
Archy [21]3 years ago
6 0

Answer:

$2.23

Step-by-step explanation:

30 - 3.24 = 26.76

26.76 ÷ 12 = 2.23

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Which of the following functions is continuous between x=-3 and x=0? choices on attachment
Damm [24]
When we say that a function is continuous between x = -3 and x = 0 it means that it exists for all values of x in between -3 and 0. Let's take a look at each choice individually:

A: f(x) = (-x + 1)/(x + 2)
Now we don't actually need to know what the graph of this function looks like to see which values it is continuous for, instead we should look at which values of x will make this function undefined - in this case that would be x = -2. The reasoning behind this is that a number divided by 0 would be undefined, so when we search for which value of x would make the denominator of the equation 0, we get:
x + 2 = 0
x = -2
Since x = -2 is within the interval [-3, 0] we cannot say the function is continuous over this interval

B: f(x) = -2/(x + 1)
Using the same method as above we get:
x + 1 = 0
x = -1
x = -1 is again within the interval [-3, 0] and so the function is not continuous within this interval

C: f(x) = 3x/(x - 2)
x - 2 = 0
x = 2
x = 2 is outside the interval of [-3, 0] and so the function is continuous within this interval and C is the correct answer.

Just for the sake of it however we can look at D as well:
D: f(x) = 1/(2x + 1)
2x + 1 = 0
x = -1/2
-1/2 is within [-3, 0] and so D is not continuous over this interval
8 0
3 years ago
What are the solutions of the equation 4X squared plus 3X equals 24 minus X
BaLLatris [955]

Answer:

x1 = -3 , x2= 2

hope it helps

8 0
3 years ago
A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average
larisa [96]

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: \mu \leq  94

Alternate Hypothesis: \mu > 94

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Using the values, we get:

t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

\alpha =0.05

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

3 0
4 years ago
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