0.05 is 1 tenth the value of

Suppose the rent for an apartment is $9,000 for the first year. The rent is expected

Maurinko [17]

Answer: $57,000

Step-by-step explanation:

Understand what is being asked. 1st yr is 9000. Yr 2 is 9000+1200= 10200. Yr 3 =10,200+1200=11,400. Yr 4 is 11,400 +1200=12,600 and Yr 5 is 12600+1200=13,800. Over the course of 5 yrs you are paying 9000+10200+11400+12600+13800 which has a total sum of $57,000.

8 0

3 years ago

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Solve these please 1. 6p-7=29 2. 12=-5d+52 3. 3(h+7)=57 4. 72=-6(2g-4)

Vilka [71]

Answer:

1. p=6

2. d=8

3. h=12

4. g=-4

Step-by-step explanation:

3 0

3 years ago

. Use the quadratic formula to solve each quadratic real equation. Round

Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

$\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}$ , with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}$

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}$

$\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5$

So B has two solutions of 5 and -1.5.

Now to C!

$\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}$

$\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}$

$\frac{44}{8} = 5.5$

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0

3 years ago

In general, the probability that it rains on Saturday is 25%. If it rains on Saturday, the probability that it rains on Sunday i

lora16 [44]

Answer:

40%

Step-by-step explanation:

From the given statements:

The probability that it rains on Saturday is 25%.

P(Sunday)=25%=0.25

Given that it rains on Saturday, the probability that it rains on Sunday is 50%.

P(Sunday|Saturday)=50%=0.5

Given that it does not rain on Saturday, the probability that it rains on Sunday is 25%.

P(Sunday|No Rain on Saturday)=25%=0.25

We are to determine the probability that it rained on Saturday given that it rained on Sunday, P(Saturday|Sunday).

P(No rain on Saturday)=1-P(Saturday)=1-0.25=0.75

Using Bayes Theorem for conditional probability:

P(Saturday|Sunday)= $\frac{P(Sunday|Saturday)P(Saturday)}{P(Sunday|Saturday)P(Saturday)+P(Sunday|No Rain on Saturday)P(No Rain on Saturday)}$

= $\frac{0.5*0.25}{0.5*0.25+0.25*0.75}$

=0.4

There is a 40% probability that it rained on Saturday given that it rains on Sunday.

5 0

3 years ago

1/3 (x-10) = -4 what is x

-BARSIC- [3]

Step-by-step explanation:

1/3x-10/3=-4

1/3x=-4+10/3

1/3x=-2/3

x=-2

7 0

3 years ago

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