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2 years ago

0.05 is 1 tenth the value of

Mathematics

1 answer:

Ganezh [65]2 years ago

8 0

The answer is .5. That is the answer because .5/10 = .05.

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39,892 to the nearest 1000 on the number line

Iteru [2.4K]

I'm pretty sure it would be 40,000 because if i'm not mistaken you meant the nearest 10,000 since the number is 39,892.

7 0

2 years ago

NEED HELP!!! Use what you know about special right triangles to find the missing measures. Show all calculations that lead to yo

Rasek [7]

Answer:a) a=22, b=11

b) m=7 $\frac{\sqrt{2} }{2}$ , n= $\frac{98-7\sqrt{2} }{2}$

Step-by-step explanation:

You should use trigonometry ratios as required and then you should use pythagoras theorem

In a) cosine(30°)= base/hypotenuse,

where 11√3 is the base

"a" is hypotenuse and

"b" is perpendicular

from this you can find the value of perpendicular then you should use pythagoras theorem to find the value of hypotenuse

pythagoras theorem is

base²+perpendicular²= hypotenuse²

Same is applied on (b) right triangle as, sine(45°)=perpendicular/hypotenuse

6 0

2 years ago

Can someone help me with this problem? Its due today plz i need help! I will give brainlist if it is right!

d1i1m1o1n [39]

Answer:

A (-4,0), B (0,3) and C (-6,5)

Step-by-step explanation:

The coordinates for A are (-4,-3) B (0,0) and C (-6,2)

From there just add 3 to all theY values

The coordinates of the translated triangle would be A (-4,0), B (0,3) and C (-6,5)

Hope that helps!

7 0

2 years ago

The sum of nine and three times a number is 57 find the number and write an equation

Temka [501]

Let "n" be a number

9 + 3n = 57
3n = 57 - 9
3n = 48
n = 48/3
n = 16

7 0

3 years ago

E xex2 + y2 + z2 dv, where e is the portion of the unit ball x2 + y2 + z2 ≤ 1 that lies in the first octant.

Jlenok [28]

$\displaystyle\iiint_{\mathcal E}xe^{x^2+y^2+z^2}\,\mathrm dV$
$=\displaystyle\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=\pi/2}\int_{\rho=0}^{\rho=1}\rho\cos\theta\sin\varphi e^{\rho^2}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$
$=\displaystyle\left(\int_{\rho=0}^{\rho=1}\rho^3e^{\rho^2}\,\mathrm d\rho\right)\left(\int_{\theta=0}^{\theta=\pi/2}\cos\theta\,\mathrm d\theta\right)\left(\int_{\varphi=0}^{\varphi=\pi/2}\sin^2\varphi\,\mathrm d\varphi\right)=\frac\pi8$

7 0

2 years ago