The functions would be:
D. y=x³
We can check it out.
(1,1); x=1; y=1 ⇒1=(1)³=1*1*1=1
(2,8); x=2; y=8 ⇒8=(2)³=2*2*2=8
(3,27); x=3; y=27 ⇒27=3³=3*3*3=27
(4,64): x=4; y=64 ⇒64=4³=4*4*4=64
(5,125); x=5; y=125 ⇔ 125=5³=5*5*5=125
Well, 1000/5 would be smaller than 2000 not bigger. You are dividing into smaller pieces not multiplying into bigger ones.
N+4=13
-4 -4
n = 9
the sum of a number(n) and 4 that is no larger than 13 is 9
-7+3/6+6=-4/12= -1/4
y+3= -1/4(x+6)
y+3= -1/4x-3/2
y=-1/4x-9/2
60% of 20 is (0.6 x 20) = 12 passes
There are a further 30 quizzes remaining (50 total during the year minus 20 already written)
80% of 30 is (0.8 x 30) = 24 passes
The student has passed (12 + 24) = 36 quizzes out of 50 total, giving an overall pass percentage of ((36 / 50) x 100)) = 72%.
