Ask question

Ask question

All categories

2 years ago

6

Please help me My parents are going to kill me if I don't do this test and I just don't know this question Please help if you do

you are a lifesaver.
Question is on the image

2 answers:

uysha [10]2 years ago

7 0

Supplementary Angle, I just took that test

Oksana_A [137]2 years ago

6 0

Answer: Supplementary angles

Step-by-step explanation:

Angle MRO is Suplementary to angle MRS. So MRO+MRS = SRO

You might be interested in

Solve 2g - 13 = 3.<br> g=

iVinArrow [24]

Answer:

8

Step-by-step explanation:

2g = 3 + 13

2g = 16

g = 16/2

g = 8

8 0

2 years ago

Read 2 more answers

a boat row a boat using a long pole of length 5.30m.when he holds the pole vertically at a particula point in the water such tha

nlexa [21]

Answer:

<u>1.06m</u>

0.2 × 5.3 = 1.06

3 0

6 months ago

The expression 55 + 14m - 2n + 3p has what terms. 2? 5? 3? 4?

dimulka [17.4K]

3 different ones. M-N-& P. Please

7 0

2 years ago

What is the slope of the line that passes through the points (2.-4 and (2,4)

Vadim26 [7]

Answer:Undefined

Step-by-step explanation:

4 0

2 years ago

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

Read 2 more answers