Answer:
the energy when it reaches the ground is equal to the energy when the spring is compressed.
Explanation:
For this comparison let's use the conservation of energy theorem.
Starting point. Compressed spring
Em₀ = K_e = ½ k x²
Final point. When the box hits the ground
Em_f = K = ½ m v²
since friction is zero, energy is conserved
Em₀ = Em_f
1 / 2k x² = ½ m v²
v =
x
Therefore, the energy when it reaches the ground is equal to the energy when the spring is compressed.
Answer:

Explanation:
Given that
V= 12 V
K=3
d= 2 mm
Area=5.00 $ 10#3 m2
Assume that
$ = Multiple sign
# = Negative sign

We Capacitance given as
For air







Net capacitance
C=C₁+C₂

We know that charge Q given as
Q= C V


Answer:
Equinox
Explanation:
It is an astronomical phenomenon that is repeated twice a year, in summer and winter, and that is caused because the axis on which our planet rotates is slightly inclined with respect to the plane of translation, this is its trajectory around the Sun.
For this reason there are two equinoxes a year, a phenomenon completely opposite to the solstice, but also marks the beginning of the spring and autumn seasons.
The equinoxes occur around March 20 or 21 and September 22 or 23, and it is the days when the Sun is exactly over the equator, which makes day and night more or less the same duration. The word ‘equinox’ comes from Latin and means precisely ‘same night’. In those two moments the part of the Earth closest to the Sun is the equator.
Answer:
The position of the spring in terms of g, m & k is 
Explanation:
Stiffness of the spring = k
Mass = m
When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.
⇒ Force exerted on the spring F = k x
⇒ m g = k x
⇒ 
This is the position of the spring in terms of g, m & k.
Answer:
the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is 
Explanation:
The free-body diagram below shows the interpretation of the question; from the diagram , the wheel that is rolling in a clockwise directio will have two velocities at point P;
- the peripheral velocity that is directed downward
along the y-axis
- the linear velocity
that is directed along the x-axis
Now;


Also,

where
(angular velocity) = 

∴ the velocity of the point P located on the horizontal diameter of the wheel at t = 1.4 s is 