1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luda [366]
3 years ago
14

MELAINE complete a long distance run at the average speed of 60 mph if it takes her 3 hours how far did she Run

Physics
1 answer:
shutvik [7]3 years ago
7 0

Answer:

Explanation:

180mile/hour

You might be interested in
I’ll give brainliest and 10 points
leonid [27]

Answer:

what's these its D okkkk

7 0
3 years ago
Where does cosmic microwave background radiation come from? A. It is radiation produced by pulsars and black holes that warps ou
LuckyWell [14K]

Answer:

C. It is radiation leftover from the Big Bang

3 0
3 years ago
Calculate the specific heat of a metal from the following data. A container made of the metal has a mass of 3.8 kg and contains
OLEGan [10]

Answer:

C = 771.35 J/kg°C

Explanation:

Here, e consider the conservation of energy equation. The conservation of energy principle states that:

Heat Given by Metal Piece = Heat Absorbed by Water + Heat Absorbed by Container

Since,

Heat Given or Absorbed by a material = m C ΔT

Therefore,

m₁CΔT₁ = m₂CΔT₂ + m₃C₃ΔT₃

where,

m₁ = Mass of Metal Piece = 2.3 kg

C = Specific Heat of Metal = ?

ΔT₁ = Change in temperature of metal piece = 165°C - 18°C = 147°C

m₂ = Mass of Metal Container = 3.8 kg

ΔT₂ = Change in temperature of metal piece = 18°C - 15°C = 3°C

m₃ = Mass of Water = 20 kg

C₃ = Specific Heat of Water = 4200 J/kg°C

ΔT₃ = Change in temperature of water = 18°C - 15°C = 3°C

Therefore,

(2.3 kg)(C)(147°C) = (3.8 kg)(C)(3°C) + (20 kg)(4186 J/kg°C)(3°C)

C[(2.3 kg)(147°C) - (3.8 kg)(3°C)] = 252000 J

C = 252000 J/326.7 kg°C

<u>C = 771.35 J/kg°C</u>

5 0
3 years ago
Average human body temperature is 98.6°F. What is the equivalent in degrees Celsius?
Gala2k [10]

37° Celsius is equal to 98.6° Fahrenheit

6 0
3 years ago
Which method will correctly determine whether the forces on an object are balanced or unbalanced?
MaRussiya [10]

For this case, the first thing you should do is define a reference system.

Once the system is defined, we must follow the following steps:

1) Do the sum of forces in a horizontal direction

2) Do the sum of forces in vertical direction

The forces will be balanced if for each direction the net force is equal to zero.

The forces will be unbalanced if for each direction the net force is nonzero.

Answer:

Add the forces in the horizontal and vertical directions separately.

6 0
3 years ago
Read 2 more answers
Other questions:
  • The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an
    12·1 answer
  • The application of force over distance is known as
    9·1 answer
  • An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. During the jump i
    7·1 answer
  • A non-conducting sphere of radius R = 3.0 cm carries a charge Q = 2.0 mC distributed uniformly throughout its volume. At what di
    8·1 answer
  • Please help with this problem ASAP!!!
    14·1 answer
  • A fatigue test was conducted in which the mean stress was 50 MPa (7250 psi) and the stress amplitude was 225 MPa (32,625 psi).
    13·1 answer
  • A student sees a newspaper ad for an apartment that has 1330 square feet (ft^2) or floor space. How many square meters of area a
    6·1 answer
  • For the love of God please help me before my mom gets angry about my horrible grades
    13·1 answer
  • Materials A, B, and C are solids that are at their melting temperatures. Material A requires 200 J to melt 4 kg, material B requ
    13·1 answer
  • Using the equation for decay, calculate the amount left of a radioactive sample amount N0 if the decay constant is 0.00125 secon
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!