Answer:
145 m
Explanation:
Given:
Wavelength (λ) = 2.9 m
we know,
c = f × λ
where,
c = speed of light ; 3.0 x 10⁸ m/s
f = frequency
thus,
substituting the values in the equation we get,
f = 1.03 x 10⁸Hz
Now,
The time period (T) = 
or
T = 
= 9.6 x 10⁻⁹ seconds
thus,
the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s
Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s
Now,
For radar to detect the object the pulse must hit the object and come back to the detector.
Hence, the shortest distance will be half the distance travelled by the pulse back and forth.
Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}
Thus, the minimum distance to target = 
= 145 m
The second and third laws of thermodynamics states that absolute zero cannot be reached. The correct option among all the options that are given in the question is the third option or option "C". Both the laws actually deal with the relations that exist between heat and other forms of energy. I hope the answer helps you.
Answer:
Given:
Weight of solid in air, 
Weight of solid in water, 
Weight of solid in liquid, 
Solution:
Calculation of:
1. Relative density of solid, 
2. Relative density of liquid, 
3. Density of liquid in S.I units:
Also, we know:
where
= density of liquid
= density of water
Now, from the above formula:
Answer:
I thibknits 175
Explanation: It's the furthest
