If g=77cm and h=85cm what is the length of f

Mathematics

1 answer:

Dmitrij [34]3 years ago

4 0

The first thing you need to do is add and then subtract

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Write an equation in point-slope form of the line using points D(0,5),E(5,8)

zhenek [66]

Answer:

<em>8 - 5 = m(5 - 0)</em>

Hope that helps you! :)

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3 years ago

A bag contains purple marbles and white marbles, 68 in total. The number of purple marbles is 4 less than 5 times the number of

galina1969 [7]

Answer: 56 purple marbles.

Step-by-step explanation:

Let be "p" the number of purple marbles in the bag and "w" the number of white marbles in the bag.

You can set up the following System of equations:

$\left \{ {{p+w=68} \atop {p=5w-4}} \right.$

You can use the Substitution method to solve the System of equations. The steps are shown below:

1. You need to substitute the second equation into the first equation:

$(5w-4)+w=68$

2. Now you must solve for "w":

$5w-4+w=68\\\\6w-4=68\\\\6w=68+4\\\\6w=72\\\\w=\frac{72}{6}\\\\w=12$

3. Substitute the value of "w" into second original equation and then evaluate in order to find the value "p":

$p=5(12)-4\\\\p=60-4\\\\p=56$

3 0

3 years ago

What the recursive formula for the sequence

klemol [59]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})$

so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

$\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}$

just a quick note on notation:

$\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}$