What is the answer please help

sleet_krkn [62]

You would use the bottom right box :)

7 0

3 years ago

Reasoning Graph the set of ordered pairs (0, 2). (1.4), (2,6). (3.8). Determine whether the relationship is a linear function Ex

polet [3.4K]

Answer:

No, it does not. See below.

Step-by-step explanation:

Lets find out the linear equation that passes trough (-2, 0) and (0, -6).

We know every linear equation has the form: y = mx + b

Where m is the slope on the curve and b the independent term.

We know that, given 2 points (x1,y1) and (x2,y2) we can find the slope m as:

m = (y2-y1)/(x2-x1)

In our case lets replace (x1,y1) and (x2,y2) by (-2, 0) and (0, -6) (notice it could be done in the inverse sense where (-2, 0) is (x2,y2) and (0, -6) is (x1,y1) ). So, our slope is:

m = [-6 - 0] / [0 - (-2)]

m = -6/2 = -3

So, we have a downward linear function with slope -3, this is:

y = -3x + b

Now, for finding b just replace any of the 2 points given in the equation. Lets replace (-2, 0):

0 = -3(-2) + b

0 = 6 + b

Subtracting 6 in both sides:

-6 = b

So, our independent term is -6 and the function is:

y = -3x - 6

Now lets see if this linear eqution passes trough (2,6). If it does, we can replace the values on the equation. Replacing x by 2:

y = -3(2) - 6 = = -6 - 6 = - 12

So, in our equation, we x is 2 y is -12, and not 6 as in the point (2,6). So, our equation does not passes trough (2,6)

5 0

2 years ago

Find the surface area of the cylinder formed by the net. Use 3.14 for π.

sineoko [7]

Answer:

138.16 square feet

Step-by-step explanation:

The surface area of the cylinder consists of one rectangle and two circles.

1. The radius of the circle is 4 ft, then the area of the circle is

$A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2$

2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.

Find the circumference:

$C=2\pi r=2\pi \cdot 4=8\pi \ ft$

Hence,

$A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2$

3. The surface area of the cylinder is

$SA=2A_{circle}+A_{rectangle}=\\ \\=2\cdot 16\pi +12\pi =32\pi +12\pi =44\pi \approx \\ \\\approx 44\cdot 3.14=138.16\ ft^2$

8 0

3 years ago

What is the length of side a?<br><br><br><br><br><br><br><br><br> Thank u

Anna007 [38]

Side a is 13 when using the pythagorean theorem

a^2 + b^2 = c^2
5^2 + 12^2 = c^2
25 + 144 = c^2
c^2 = 169
c = 13

4 0

2 years ago

Twin brothers, Billy and Bobby, can mow their grandparent’s lawn together in 63 minutes. Billy could mow the lawn by himself in

Pepsi [2]

Answer:

<h2>140 minutes</h2>

Step-by-step explanation:

this problem focuses on the combined work rate

both can finish the work under 63 minute

let bobby mow the lawn in x minute

Billy will then mow the lawn in x-25 minutes

Let the completed job = 1 (a mowed lawn)

we can now apply the combined work formula for the two boys as

$\frac{63}{x}+\frac{63}{x-25}=1$

multiplying through by x(x-25 )we have

$63(x-25)+63x= x(x-25)$

open bracket we have

$63x-1575+63x= x^2-25x$

rearranging and collecting like terms we have

$0=x^2-25x-63x-63x+1575 \\\\0=x^2-151x+1575 \\\\x^2-151x+1575=0$

we can now use the quadractic formula

$x=\frac{-b\frac{+}{} \sqrt{b^2-4ac} }{2a}$

a= 1

b= -151

c= 1575

$x=\frac{-(-151)\frac{+}{} \sqrt{151^2-4*1*1575} }{2*1}$

$x=\frac{-(-151)\frac{+}{} \sqrt{22801-6300} }{2} \\\\x=\frac{-(-151)\frac{+}{} \sqrt{16501} }{2} \\\\x=\frac{-(-151)\frac{+}{} 128.45}{2} \\\\$

$x=\frac{-(-151)+128.45}{2} \\\\\x=\frac{279.45}{2} \\\\x=139.72 \\\\\\x=\frac{-(-151)-128.45}{2}\\\\x=\frac{151-128.45}{2}\\\\x=\frac{22.55}{2}\\\\x=11.27$

the first answer x= 139.72 approximately 140 minutes mins is correct for Bobby's time

let us check

$\frac{63}{140}+\frac{63}{140-25}=1\\\\\\0.45+\frac{63}{115} =1\\\\0.45+0.5478=1\\0.997 =1$

we can see that the solution approximates to 1

8 0

3 years ago