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Tomtit [17]
3 years ago
12

What is the answer please help

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

0.9 seconds is the correct answer

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Formula of perimeter and area ​
OverLord2011 [107]

Answer:

Perimeter: 4 * s

Area: S 2

Diagonal: s 2 \sqrt {2} 2

Area of square when diagonal is given = 1 2 × d 2 \frac {1} {2}\times d^ {2} 21 ​ × d2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
PLS HELPPPP IVE ASKED THIS 3 TIMES (3y + 11) (7x - 30) (5x + 14)Write the equation of the line that passes through the points (0
zavuch27 [327]

Answer: 2x + 3y =  33

4 0
1 year ago
Please give 5 addition of polynomial examples​
Dafna1 [17]

Answer:

Addition of Polynomials

1Add: 3x3 – 5x2 + 8x + 10, 15x3 – 6x – 23, 9x2 – 4x + 15 and -8x3 + 2x2 – 7x.

2Add: 7a + 5b, 6a – 6b + 3c and -5a + 7b + 4c. ...

3Add: 3a2 + ab – b2, -a2 + 2ab + 3b2 and 3a2 – 10ab + 4b2 ...

4Add: 5x + 3y, 4x – 4y + z and -3x + 5y + 2z. First we need to write in the addition form. ...

Step-by-step explanation:

Hope it helps ya ItzAlex

3 0
2 years ago
Can anyone tell me why by direct substitution of x, the equation (circled ones) equals to the indeterminate form, 0/0? When you
Katena32 [7]

Answer:

See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

hx=15

Dividing both sides by h:

x=15/h

For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

225/h^2-k=0

k=225/h^2

So if we wanted to evaluate the following limit:

Lim x->15/h ( x^2-k ) / ( hx-15 )

Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

Lim x->3 ( x^2-k ) / ( hx-15 )

Comparing the two limits h=5 and k=225/h^2=225/25=9.

3 0
3 years ago
9. Water is added to two containers for 16 minutes. The equations below model the ounces of
Vladimir [108]

The two containers hold 328 ounces at the they hold same amount of water.

<u>Step-by-step explanation:</u>

The equations below model the ounces of  water, y, in each container after x minutes.

y = 16x + 104

y = -2x^{2} +40x+160

At the time after the start when the containers hold  the same amount of water, the two equations must be equal.

⇒ 16 x + 104 = -2x^{2}  + 40 x + 160

The first step is to divide everything by 2 to make it simplified.

⇒ 8 x + 52 = - x^2 +20 x + 80

Now put everything on the left .

x^2 + 8 x - 20 x + 52 - 80 = 0

Add the like terms together to further reduce the equation

x^2 - 12 x - 28 = 0

Factorizing the equation to find the roots of the equation.

Here, b = -12 and c = -28

where,

  • b is the sum of the roots ⇒ -14 + 2 = -12
  • c is the product of the roots ⇒ -14 × 2 = -28
  • Therefore, (x-14) (x+2) = 0
  • The solution is x = -2 or x = 14

Take x = 14  and substitute in any of the given two equations,

⇒ y = 16(14) + 104

⇒ y =224+104

⇒ 328 ounces

∴ The two containers hold 328 ounces at the they hold same amount of water.

5 0
3 years ago
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