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Answer:
x = -203/23
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
y = -23(x + 9) + 4
y = 0
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute in <em>y</em>: 0 = -23(x + 9) + 4
- [Subtraction Property of Equality] Subtract 4 on both sides: -4 = -23(x + 9)
- [Division Property of Equality] Divide -23 on both sides: 4/23 = x + 9
- [Subtraction Property of Equality] Subtract 9 on both sides: -203/23 = x
- Rewrite: x = -203/23
Answer:
The zeroes in this equation are -5, -4, and 5
Step-by-step explanation:
In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.
r^3 + 4r^2
r^2(r + 4)
Now the second half.
-25r - 100
-25(r + 4)
Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.
(r^2 - 25)(r + 4)
And we can further factor the first parenthesis using the difference of two squares
(r^2 - 25)(r + 4)
(r + 5)(r - 5)(r + 4)
Now that we are fully factored, set each parenthesis equal to 0 and solve for x.
r + 5 = 0
r = -5
r - 5 = 0
r = 5
r + 4 = 0
r = -4
Answer:
p=4CP - 26
C= p/4P + 13/2P
P= P/4C +13/2C
Step-by-step explanation:
Step-by-step explanation:
I think we cannot find the sum because it will continue on so the series is multiply by 4
