Wx+yz=bc
-yz. -yz
Wx=bc-yz
Wx/W=bc-yz/W
x=bc-yz/W
H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer:
C
Step-by-step explanation:
Number 4
Answer:
$660
Step-by-step explanation:
1: Change 5% to a decimal. (0.05)
2: Multiply 600 X 0.05 X 2(years)
3: Add 60 and 600
4: $660
Answer:
1/10
Step-by-step explanation:
6/10 is more than 1/10 bc 6 is bigger than 1 :)
