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Kryger [21]
3 years ago
9

Match each binomial with its factors. Tiles 16x2 − 1 (2x + 1)(2x − 1) 16x2 − 4 (2x + 3)(2x − 3) 16x2 + 1 4(2x + 1)(2x − 1) 4x2 −

1 (4x − 1)(4x + 1) 4x2 − 9 Pairs
Mathematics
1 answer:
Ghella [55]3 years ago
6 0
You can do this in two ways. The easiest way using the special case formulas since these are perfect squares. Another would be multiplying the pairs and seeing what matches the other.   
Here are the formulas for special cases:

a^{2}  + 2ab + b^{2} = (a+b)^{2}
a^{2} - 2ab + b^{2} = (a-b)^{2}
a^{2} - b^{2} = (a+b)(a-b)

1. (2x+1)(2x-1) This follows the third formula where a=2x and b = 1
(2x+1)(2x-1) = 4x^{2}-1^{2} = 4x^{2}-1

2. <span>(2x + 3)(2x − 3) This also follows the third formula where a=2x and b = 3
</span>(2x+3)(2x-3) = 4x^{2}-3^{2} = 4x^{2}-9

3. <span> 4(2x + 1)(2x − 1) This follows the third formula but the result should be multiplied by 4. We can do this by combining the pairs first before multiplying it by 4. The associative property of multiplication allows this.
</span>4(2x+1)(2x-1) = 4(4x^{2}-1^{2}) = 4(4x^{2}-1)

From here we can use the distributive property:
4(4x^{2}-1) = 16x^{2}-4

4. <span>(4x − 1)(4x + 1) This also uses the third formula where a= 4x and b= 1</span>
(4x-1)(4x+1) = 16x^{2}-1^{2} = 16x^{2}-1

So let's match up the pairs with their results:
16x^{2}-1=(4x-1)(4x+1)
16x^{2}-4 = 4(2x + 1)(2x − 1)
4x^{2}-1 = (2x+1)(2x-1)
4x^{2}-9 = (2x+3)(2x-3)

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Answer:

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9p + 3 - 6p + 3 = 0

3p + 6 =0

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there for the answer would be

{(-2, 5)}

Hopefully this was helpful <3 :3

5 0
3 years ago
Complete the Table
lianna [129]

Answer:

a= 6

b = 7

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d = 7

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Step-by-step explanation:

Notice that the bike is 6 feet above the ground to start with, so when it starts rolling, the green dot is exactly 6 feet from the ground, which gives a=6

when the distance covered by the bike is \frac{\pi}{2}, (see first red dot in the attached image), the position of the green dot is exactly 1 foot added to 6 ft= 7 feet

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when the distance covered is \frac{3\pi}{2}, the green dot is at the position of the third red dot in the attached image., that it exactly one foot added to 6 feet = 7 ft which gives the value of d = 7

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3 years ago
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vitfil [10]
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Here, we need to do the inverse operation, and apply it to BOTH sides of teh equation.

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3 years ago
Read 2 more answers
Simplify. (x2+2x-4)+(2x-5x-3)​
vladimir2022 [97]

Answer:

Step by Step Solution

More Icon

STEP

1

:

3

Simplify ——

x2

Equation at the end of step

1

:

3

((((2•(x2))-5x)-——)+2x)-3

x2

STEP

2

:

Equation at the end of step

2

:

3

(((2x2 - 5x) - ——) + 2x) - 3

x2

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1 Subtracting a fraction from a whole

Rewrite the whole as a fraction using x2 as the denominator :

2x2 - 5x (2x2 - 5x) • x2

2x2 - 5x = ———————— = ———————————————

1 x2

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

2x2 - 5x = x • (2x - 5)

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • (2x-5) • x2 - (3) 2x4 - 5x3 - 3

————————————————————— = —————————————

x2 x2

Equation at the end of step

4

:

(2x4 - 5x3 - 3)

(——————————————— + 2x) - 3

x2

STEP

5

:

Rewriting the whole as an Equivalent Fraction :

5.1 Adding a whole to a fraction

Rewrite the whole as a fraction using x2 as the denominator :

2x 2x • x2

2x = —— = ———————

1 x2

Polynomial Roots Calculator :

5.2 Find roots (zeroes) of : F(x) = 2x4 - 5x3 - 3

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers

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