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zavuch27 [327]
3 years ago
9

Mrs. Sampson was in a submarine that was 200 feet below sea level. Then it rose 120 feet. After it dove 34 more feet, where was

Mrs. Sampson's submarine located
114 feet
114 feet below sea level
354 feet
354 feet below sea level
Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

-114 or 114 ft below sea level.

Step-by-step explanation:

All you have to do is do -200 + 120 - 34 = -114. Or if you wanted too, you could add -200 and -34 togther giving you -234 and then just add 120 still giving you -114. Leaving you with a final answer of -114 or B.

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Find an angle in each quadrant with a common reference angle with 77°, from 0°≤θ<360°
mr Goodwill [35]

Answer:

Q1: 77°, Q2: 103°, Q3: 257°, Q4: 283°

Step-by-step explanation:

Note: Q1 = Quadrant 1

Q1: 77°

Q2: 180° - 77° = 103°

Q3: 180° + 77° = 257°

Q4: 360° - 77° = 283°

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3 years ago
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Han has 5 pencils and Andre has 8
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Answer:

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Step-by-step explanation:

Together: 13

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3 years ago
Consider rolling two fair dice one 3-sided the other 5-sided
Ne4ueva [31]

Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose

1\leq x\leq 3,\quad 1\leq y \leq 5

We have P(X=x)=\frac{1}{3} and P(Y=y)=\frac{1}{5}, because the dice are fair.

Now we use the assumption of independence to claim that

P(X=x, Y=y) = P(X=x)\cdot P(Y=y) =\dfrac{1}{3}\cdot\dfrac{1}{5} = \dfrac{1}{15}

Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:

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  • 5 in three possible ways
  • 6 in three possible ways
  • 7 in two possible ways
  • 8 in a unique way

This implies that the probabilities of the outcomes of W=X+Y are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5

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Answer: B. $430.80

Step-by-step explanation:

Given : Last year Baron Enterprises had $800 million of sales.

It had $270 million of fixed assets that were used at 65% (=0.65) of capacity last year.

Now, the used asset = 0.65\times270=\$175.5million

Now, Baron Enterprises had $800 million of sales in $175.5 million of assets , if we use all of $270 million of fixed assets , then the sales will be :-

\dfrac{800}{175.5}\times270=1230.76923077\approx1230.80\text{ million}

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Hence, the increase in Baron's ( in million ) sales before it is required to increase its fixed assets = $430.80

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