Answer:
x² + 5x + 6
Step-by-step explanation:
Foil means first, outside, inside, last
First: (x+2)(x+3)
x × x = x²
Inside: (x+2)(x+3)
x × 3 = 3x
Ouside: (x+2)(x+3)
2 × x = 2x
Last: (x+2)(x+3)
2 × 3 = 6
adding them together:
x² + 3x + 2x + 6 = x² + 5x + 6
X²(x - 4) +4 (x - 4)
(x² + 4) (x - 4)
First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)
Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)
The key is to find the first term a(1) and the difference d.
in an arithmetic sequence, the nth term is the first term +(n-1)d
the firs three terms: a(1), a(1)+d, a(1)+2d
the next three terms: a(1)+3d, a(1)+4d, a(1)+5d,
a(1) + a(1)+d +a(1)+2d=108
a(1)+3d + a(1)+4d + a(1)+5d=183
subtract the first equation from the second equation: 9d=75, d=75/9=25/3
Plug d=25/3 in the first equation to find a(1): a(1)=83/3
the 11th term is: a(1)+(25/3)(11-1)=83/3 +250/3=111
Please double check my calculation. <span />
