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3 years ago

Please help if you know the answer

Mathematics

2 answers:

Natali5045456 [20]3 years ago

5 0

The correct answer of this problem is C

worty [1.4K]3 years ago

3 0

It's C. When you're dividing g(x) by f(x), you get the equations in both B. and C., but C is more correct because you can't have x=-1/3 because the function is undefined at that number (you can't have the denominator equal 0)

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A bouncing ball reaches a height of 54 inches at its first peak, 36 inches at its second peak, and 24 inches at its third peak.

sesenic [268]

Answer:

f(x) = 54(two-thirds) Superscript x minus 1

Step-by-step explanation:

Given that:

First peak : 36 / 54=2/3

Second peak : 24 / 36 = 2/3

The common ratio here is 2/3 ; which mean each bounce height is 2/3 of previous height

Modeling this using geometric progression :

An=a1r^(n-1)

An = nth term of a geometric progression

a1=first term

r=common ratio = 2/3

n = nth term

a1=54

Substituting into the above formular :

An=54(2/3)^(n-1)

4 0

2 years ago

Read 2 more answers

Kirsten calculated the mean of 10 quiz scores. Later she was told there was an error in grading one of her quizzes. A quiz score

inessss [21]

The mean will be 5 points higher...so...c would be the answer!

3 0

3 years ago

Read 2 more answers

Write the ratio 48:30:42 in its simplest form

Zielflug [23.3K]

Answer- 8:5:7

Explanation:
Find the greatest common factor for all of them. Which is 6.
Then you just divide each number by 6
48/6= 8
30/6= 5
42/6= 7
Making it 8:5:7

7 0

2 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

2 years ago

The graph shows six labeled points. How many distinct circles of radius 2 units are in the coordinate plane and pass through exa

Nostrana [21]

if there was a graph I would be able to help you but you have on here how many distinct Circles of radius 2 units are on the coordinate plane and pass through exactly two of the labeled point on this graph? Where is the graph?

3 0

2 years ago