Answer:
yes the answer is c
Step-by-step explanation:
Table:
x y
-3 0.5
-2 1
-1 2.5
0 5
1 8.5
Now, y = ax^2 + bx + c
Start replacing x = 0 and y = 5
5 = a(0) + b(0) + c => c = 5.
Now, replace any other two pair of data:
(-2, 1) => -1 = a(-2)^2 + b(-2)
-1 = 4a - 2b
(1, 8.5) => 8.5 = a(1)^2 + b(1)
8.5 = a + b
Solve the system
4a - 2b = - 1
a + b = 8.5
=>
4a - 2b = - 1
2a + 2b = 17
-------------------------
6a = 16
=> a = 16 / 6 = 8/3
b = 8.5 - a = 17/2 - 8/3 = 35/6
=> y = (8/3)x^2 + (35/6)x + 5 <--------- answer
Step-by-step explanation:
a(n) = a +(n-1)d
a=20
d=26-20=6
°.° a(n) = 20 +(n–1)6
a(1) = 20 +(1–1)6=20
hope this helps
Answer:
17 cows and 6 geese
Step-by-step explanation:
1. set up two equations:
C + G = 23 (number of cows and geese = total number of animals)
4C + 2G = 80 (cows have 4 legs, geese have 2 legs and the total # of legs is 80)
2. 2(C+G)=2(23) ===> 2C + 2G = 46
3. subtract 4C + 2G = 80 and 2C + 2G = 46 to equal 2C=34, divide by 2 and C=17 (17 cows)
4. apply 17 back to the original (C + G = 23) equation to get: 17 + G = 23, subtract 17 from 23 and G=6 (6 geese)
i hope the way i explained it was clear! :)
U have to have the number of the Pentagon before it was dilated
