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Bas_tet [7]
3 years ago
12

Write 64,500 in scientific notation

Mathematics
1 answer:
lukranit [14]3 years ago
5 0
6.45 x 10 to the 4th. 
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Consider the following geometric series. [infinity] (−7)n − 1 8n n = 1. Find the common ratio. Determine whether the geometric s
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d67d6d 34r2

Step-by-step explanation:

d53eududc6ttd5cf

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The factory has 6 cutting machines. Each cutting machine cuts 105 parts every 3 minutes. How many parts can all 6 cutting machin
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2 years ago
An online video store charges $24 please help
mr Goodwill [35]

Answer:

B. 24d + 4; $76

Step-by-step explanation:

Part 1: If the online store charges $24 per DVD, this is the same as saying "24 multiplied by the number of DVDs bought".

It's given that "d" represents the number of DVDs

  • So the first part of the variable expression is: 24d

If the online store also charges an additional $4 per <em>order,</em> that means that it's only $4 extra for the whole order. NOT per DVD you buy.

  • Result: 24d + 4

Part 2: If someone were to buy 3 DVDs, that would mean that d = 3.

To find the total cost, substitute 3 for d into the expression.

  • 24d + 4
  • 24(3) + 4
  • 72 + 4 = 76
  • Result: $76
4 0
3 years ago
The lengths of the sides of a triangle are 5, 12, and 13. What is the length of the altitude drawn to the side with length equal
mario62 [17]

Answer:  using  A= bh/2   THe height is 9.23

Step-by-step explanation:  First, with the Right Angle at the bottom, usr the sides to compute the area:  12*5=60

THen Imagine the side=13 as the base, so you have  b=13 for the formula

use the formula A= bh/2

60 = 13h/2 ==> 2(60) =13h --> 120/13 = h

h = 9.23

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3 years ago
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<span>Given that the orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P = a^(3/2). If Saturn’s orbital period is 29.5 years, then 29.5 = a^(3/2) a = (29.5)^(2/3) = 9.547 Therefore, Saturn's distance from the sun is 9.547 astronomical units.</span>
7 0
3 years ago
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