The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is 
<h3>How to determine the equation of the hyperbola?</h3>
The given parameters are:
- Directrices at x = ±2
- Foci at (5, 0) and (−5, 0)
The foci of a hyperbola are represented as:
Foci = (k ± c, h)
The center is:
Center = (h,k)
And the directrix is:
Directrix, x = h ± a²/c
By comparison, we have:
k ± c = ±5
h = 0
h ± a²/c = ±2
Substitute h = 0 in h ± a²/c = ±2
0 ± a²/c = ±2
This gives
a²/c = 2
Multiply both sides by c
a² = 2c
k ± c = ±5 means that:
k ± c = 0 ± 5
By comparison, we have:
k = 0 and c = 5
Substitute c = 5 in a² = 2c
a² = 2 * 5
a² = 10
Next, we calculate b using:
b² = c² - a²
This gives
b² = 5² - 10
Evaluate
b² = 15
The hyperbola is represented as:
So, we have:
Evaluate
Hence, the equation of the hyperbola is
Read more about hyperbola at:
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{k^2 + 2k + 1 = 25, k^2 + 2k + 1 = 64}
{k^2 + 2k - 24 = 0, k^2 + 2k - 63 = 0}
{(k - 4)(k + 6) = 0, (k - 7)(k + 9) = 0}
{k = -6, 4, -9, 7)
Therefore, range = {-9, -6, 4, 7)
The five is in the tenth place so it is 50
This written as an expression is 7 >= w > -1
Hope this helps!
Answer:
315 chocolate
Step-by-step explanation:
Let Sam's chocolate be S
Let Clariss's chocolate be C
When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.
This can be written as:
C = 5S
The sum of their chocolate is 504 i.e
S + C = 504
Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:
S + C = 504
But: C = 5S
S + 5S = 504
6S = 504
Divide both side by 6
S = 504/6
S = 84.
C = 5S = 5 x 84 = 420
Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.
Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:
Amount of chocolate that Clarissa has a first = 420 – 105 = 315
Therefore, Clarissa had 315 chocolate at first.
