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2 years ago

Find the volume of the cylinder that has a radius of 7cm and a hight of Ilcm

Mathematics

1 answer:

Keith_Richards [23]2 years ago

4 0

Answer:

$539\pi cm^{3}$

Step-by-step explanation:

the volume of a cylinder is $V=\pi r^{2} h$

Let r=7cm and h=11cm

V= $7^{2}$ ·11· $\pi$

V=539 $\pi$ $cm^{3}$ or 1693.31844 $cm^{3}$

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URGENT HELP ME PLEASE

Trava [24]

Answer:

(a) $\log_3(\dfrac{81}{3})=3$

(b) $\log_5(\dfrac{625}{25})=2$

(d) $\log_4(\dfrac{64}{16})=1$

(e) $\log_6(36^4)=8$

(f) $\log(100^3)=6$

Step-by-step explanation:

Let as consider the given equations are $\log_3(\dfrac{81}{3})=?,\log_5(\dfrac{625}{25})=?,\log_2(\dfrac{64}{8})=?,\log_4(\dfrac{64}{16})=?,\log_6(36^4)=?,\log(100^3)=?$ .

(a)

$\log_3(\dfrac{81}{3})=\log_3(27)$

$\log_3(\dfrac{81}{3})=\log_3(3^3)$

$\log_3(\dfrac{81}{3})=3$ $[\because \log_aa^x=x]$

(b)

$\log_5(\dfrac{625}{25})=\log_5(25)$

$\log_5(\dfrac{625}{25})=\log_5(5^2)$

$\log_5(\dfrac{625}{25})=2$ $[\because \log_aa^x=x]$

(c)

$\log_2(\dfrac{64}{8})=\log_2(8)$

$\log_2(\dfrac{64}{8})=\log_2(2^3)$

$\log_2(\dfrac{64}{8})=3$ $[\because \log_aa^x=x]$

(d)

$\log_4(\dfrac{64}{16})=\log_4(4)$

$\log_4(\dfrac{64}{16})=1$ $[\because \log_aa^x=x]$

(e)

$\log_6(36^4)=\log_6((6^2)^4)$

$\log_6(36^4)=\log_6(6^8)$

$\log_6(36^4)=8$ $[\because \log_aa^x=x]$

(f)

$\log(100^3)=\log((10^2)^3)$

$\log(100^3)=\log(10^6)$

$\log(100^3)=6$ $[\because \log10^x=x]$

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2 years ago

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Sergeeva-Olga [200]

Hint: Try using the Pythagorean thereom to solve it.

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2 years ago

50 is 15% of what number?

Mashcka [7]

Converting percentage to a decimal :
50%= 50 / 100 = 0.5

What is 50% of 15
=50% * 15
=0.5 * 15
=7.5

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2 years ago

Why might you want to use the commutative property to change the order of the integers in the following sum before adding

Delicious77 [7]

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2 years ago

This box plot shows information about the marks scored in a test.

aliina [53]

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hope this helps :)

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1 year ago