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elixir [45]
3 years ago
10

A set of equations is shown above. Which method eliminates one of the variables? A) Multiply equation A by -1/3 and add the resu

lt to equation B. B) Multiply equation B by 3 and add the result to equation A. C) Multply equation A by 2 and equation B by -6 and add the results together. D) Multiply equation B by 5 and equation A by 4 and add the results together.

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:


Step-by-step explanation:

Multiplying Equation A by (1/3) and adding the result to Equation B will do the trick.  Let's actually solve the problem!

Equation A:  (5/3)x + 3y = 12

Equation B:    4x     -  3y = 8

                    ---------------------------

                     (5/3 + 12/3)x = 15        Note how this has eliminated the variable

                            (17/3)x = 15           y.

                                   x = (3/17)(15)

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3 years ago
The first two terms of an arithmetic sequence are 7 and 4. Find the 7th term.
kobusy [5.1K]

EXPLANATION

If the first two terms of an arithmetic sequence are 7 and 4, then we know that an arithmetic sequence has a constant difference d and is defined by

a_n=a_1+(n+1)d

Check wheter the difference is constant:

Compute the differences of all the adjacent terms:

d=a_{n+1}-a_n

Replacing terms:

4-7 = -3

The difference between all of the adjacent terms is the same and equal to

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The first element of the sequence is

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Therefore, the nth term is computed by

d= -3

a_n=7+\text{ (n-1)}\cdot(-3)

Refine

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a_n=-3n+10

Now, replacing n=7

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So, the answer is -11.

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Step-by-step explanation:

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