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3 years ago

Use the distributive property to find an expression that is equivalent to 2x(x + 7)-(3x +1)

Mathematics

1 answer:

zaharov [31]3 years ago

7 0

Given expression:

2x(x + 7)-(3x +1);

To distribute implies to spread a process equally in an expression. Often times, the distributive property is used for expressions inside parentheses;

2x(x + 7)-(3x +1)

Distribute 2x over the first parentheses;

the negative sign distributes over the second part

= (2x² + 14x) - 3x -1

= 2x² + 14x -3x -1

Add like terms;

= 2x² + 11x -1

This expression 2x² + 11x -1 is equal to the given one

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At a candy store you can pay $16.10 for 7 giant lollipop what would be the cost for 6 lollipops?

Alex Ar [27]

Answer: $13.80 for 6 giant lollipops

Step-by-step explanation: To find the cost of 6 giant lollipops at the candy store, we first need to find the unit price for a giant lollipop.

Unit price means the cost per unit,

in this case, the cost per giant lollipop.

Since we know that it costs $16.10 for 7 giant lollipops, to find the cost

for 1 giant lollipop, we need to 16.10 by 7.

16.10 divided by 7 is 2.3.

This means that each lollipop is $2.30.

Now to find the cost for 6, we multiply

the cost per 1 lollipop by 6.

So we have 2.30 × 6 which is $13.80.

So the cost for 6 lollipops at the candy store is $13.80.

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3 years ago

Type the expressions as radicals.<br> Y^5/2

Lapatulllka [165]

Answer:

it will be square root y^5

Step-by-step explanation: Apply the rule x m/n=n√x m to rewrite the exponentiation as a radical.

7 0

2 years ago

Write the equation of the line that passes

Vinvika [58]

Answer:

The slope is -4.

Step-by-step explanation:

Slope formula:

$\displaystyle \frac{y_2-y_1}{x_2-x_1}=\frac{rise}{run}$

$\displaystyle \frac{(-9)-(-5)}{1-0}=\frac{-4}{1}=-4$

Therefore, the slope is -4, and the correct answer is -4.

Hope this helps!

8 0

2 years ago

Read 2 more answers

How do i rewrite y=8 (x - 5) (x +2) in standard form

Komok [63]

Answer:

Its already in standard form. LoL

Step-by-step explanation:

y=(x−5)(x+2)

6 0

3 years ago

Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies ac

Shtirlitz [24]

Answer:

a) $\mu -3\sigma = 336-3*6=318$

$\mu+-3\sigma = 336+3*6=354$

b) For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

Step-by-step explanation:

Assuming this question : "Bigger animals tend to carry their young longer before birth. The length of horse pregnancies from conception to birth varies according to a roughly normal distribution with mean 336 days and standard deviation 6 days. Use the 68-95-99.7 rule to answer the following questions. "

(a) Almost all (99.7%) horse pregnancies fall in what range of lengths?

First we need to remember the concept of empirical rule.

From this case we assume that $X\sim N(\mu = 336. \sigma =6)$ where X represent the random variable "length of horse pregnancies from conception to birth"

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

From the empirical rule we know that we have 99.7% of the data within 3 deviations from the mean so then we can find the limits for this case with this:

$\mu -3\sigma = 336-3*6=318$

$\mu+-3\sigma = 336+3*6=354$

(b) What percent of horse pregnancies are longer than 342 days?

For this case we know that within 1 deviation from the mean we have 68% of the data, and on the tails we need to have 100-68 =32% of the data with each tail with 16%. The value 342 is above the mean one deviation so then we need to have accumulated below this value 68% +(100-68)/2 = 68%+16% =84%

And then the % above would be 100-84= 16%

7 0

3 years ago