<span> 5x-4y=40
</span><span>x intercepts, y = 0
</span>5x =40
x = 8
y intercepts, x = 0
-4y =40
y = -10
answer
x intercepts (8,0)
y intercepts (0, -10)
Answer:
To find the slope of a line, given its equation, we have to rearrange its terms to the slope-intercept form y = mx + b. Here, 'm' gives the slope and 'b' gives the y-intercept of the equation. We rewrite the standard form of the equation of the line to the slope-intercept form y = mx + b.
Step-by-step explanation:
I hope this helps:)
Answer: D(t) = 20°*cos((pi/4)*t) + 55°
Step-by-step explanation:
using that t = 0 is midnight, we know.
We know:
Max temp = 75°
Min temp = 35° (occurs at t = 4 hours)
Now we can model this as:
D(t) = A*cos(c*t) + B
Where A, c and B are constants.
we have a minimum at t = 4 hours, a minimum means that cos(c*t) = -1
then we have that:
D(4) = A*cos(c*4) + B = A*(-1) + B = 35°
here we also have that cos(c*4) = -1
this means that c*4 = pi
c = pi/4
We also have that the maximum temperature is 75°, the maximum temperature is when cos(c*t) = 1
D(t0) = A*(1) + B = 75°
with this we can find the values of A and B.
-A + B = 35°
A + B = 75°
We isolate B in the first equation and then replace it in the second equation.
B = 35° + A
A + B = 75°
A + 35° + A = 75°
2A = 40°
A = 40°/2 = 20°
B = 35° + 20° = 55°.
Our equation is:
D(t) = 20°*cos((pi/4)*t) + 55°
Answer:
The distance between (-8,-2) and (-6,2) is:
Step-by-step explanation:
Given the points
Computing the distance between (x₁, y₁) and (x₂, y₂)
substituting (x₁, y₁) = (-8,-2) and (x₂, y₂) = (-6,2)
∵ ![\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D)
∵ ![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
Therefore, the distance between (-8,-2) and (-6,2) is:
