Question

Each triangle in the net has a base length that measures 6 inches and a height that measures 4 inches. What is the surface area of the pyramid that can be formed from this net?

Answer 1

Answer:

$Area= 84 \ in^2$

Step-by-step explanation:

The surface area of a pyramid is equivalent to the area of its base plus area of it's 4 triangles.

#The pyramid has a square base with lengths equal to the triangle's base length:

$A=s\times s=s^2\\\\=6^2\\\\=36\ in^2$

#The area of the side triangles is calculated as:

$A=0.5bh\\\\=0.5\times 6\times 4\\\\=12\\\\\therefore A_t=4A=12\times 4=48\ in^2$

We sum the two area to find the net surface area of the pyramid:

$A=A_b+A_t\\\\=36+48\\\\=84\ in^2$

Hence, the pyramid's surface area is $84 \ in^2$