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Marianna [84]
3 years ago
6

ASAP can someone help me solve this problem​

Mathematics
1 answer:
sveta [45]3 years ago
3 0

Answer:

Step-by-step explanation:

x° + y° = 180°

2y° - 0.5x° = 180°

y° = 108°

x° = 72°

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Answer:

-16.3  ≥  q

Step-by-step explanation:

–5.3 ≥ 6.7 + 4.3 + q

Combine like terms

–5.3 ≥ 11 + q

Subtract 11 from each side

–5.3-11 ≥ 11-11 + q

-16.3  ≥  q

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Which expression is equivalent to 27 ( − 2 3 x + 1 3 ) − 5 x ?
klemol [59]

Answer:

KINGSHIP NO NIJINSKY

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3 years ago
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

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2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

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b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

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$d=\frac{-7\pm\sqrt{81}}{-4}$

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It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

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V=\pi (2.5)^2 \cdot 5

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$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
3 years ago
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dedylja [7]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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What expression is equivalent to 4 to the negative 3 power
Elina [12.6K]

Answer:

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