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3 years ago

What is 10x-2(4x+5)+6

Mathematics

2 answers:

guapka [62]3 years ago

8 0

Answer:

2x - 4

Step-by-step explanation:

Expand the brackets.

10x - 2(4x+5) + 6 = 10x - 8x - 10 + 6

Evaluate like terms.

10x - 8x - 10 + 6 = 2x - 4

Gala2k [10]3 years ago

6 0

Answer:

Step-by-step explanation:

10x-2(4x+5)+6 foil

10x-8x-10+6 combine like terms

2x-4

If you need to find x

2x=4 divide by 2

x=2

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Lana71 [14]

Answer:

CV for A = 21.8%

CV for B = 15.5%

Step-by-step explanation:

The formula for coefficient of variation is:

CV = Standard Deviation / Mean

So,

For A:

Mean = Sum/No. of items

= 391300/14

=$27950

and

SD = $6085.31

CV for A = 6085.31/27950 * 100

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Rounding off to one decimal

CV for A = 21.8%

For B:

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3 years ago

Point K is on line JL. given JL =4x, JK= 2x+3, and KL=x, determine the numerical length of kl

balandron [24]

Hi! I'm happy to help!

Our total line is JL (4x), and it is split into two parts: JK, and KL. We have our values, and we know that JK+KL=JL, so we can substitute our values and solve for x:

4x=(2x+3)+(x)

4x=3x+3

To solve for x, we have to isolate it on one side of the equation.

First, let's subtract 3x from both sides so that we can isolate x:

4x=3x+3

-3x -3x

x=3

<u>So, our x=3, which means that KL=3.</u>

I hope this was helpful, keep learning! :D

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3 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
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\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
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\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
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when will it reach the ground level? let's set s(t) = 0

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25=t^2\implies \boxed{5=t}$

part B) check the picture below

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