3/(x^3y)
7/(xy^4)
To find the LCD you have to use the HIGHEST power of the variables.
x^3y^4 would be the LCD
LETTER A
Hey there!
The answer to your question is
We can see that we are adding two numbers, and the second is , and that is equal to
So,
Hope it helps and have a great day!
Answer is D. f(x) = x + 1
when x = -1, f(-1) = -1 + 1 = 0
when x = 0, f(0) = 0 + 1 = 1
when x = 1, f(1) = 1 + 1 = 2
when x = 2, f(2) = 2 + 1 = 3
Hope it helps
a+b=18
2a+3b=40
Here's <em>two</em> solutions:
A) Multiply the first equation by (-2) & sum then the two equations, resulting ''b''. Or, multiply that first equation by (-3) Summing them you get ''a''. Whatever you obtain, introduce it into an equation and obtain the other one.
B) You have a system of two equation with two unknown terms. Get one unknown term (e.g. ''a'') out of the first equation (a=18-b) & introduce it (18-b) into the other equation, the second one, instead of that unknown term, and you'll get this second equation written within just one unknown term ( 2(18-b)+3b=40 ; 36-2b+3b=40. With the term this way defined, you'll have also the first one.
x+y=18; 2x+3y=40
y=18-x, 2x+3(18-x)=40
2x+54-3x=40
-x=-14
x=14
14+y=18, y=4
14+4=18
2(14)+3(4)=40, 28+12=40