A.) R(20) = -10(20)^2 + 800(20) = -10(400) + 16000 = -4000 + 16000 = $12,000
R(25) = -10(25)^2 + 800(25) = -10(625) + 20000 = -6250 + 20000 = $13,750
R(30) = -10(30)^2 + 800(30) = -10(900) + 24000 = -9000 + 24000 = $15,000
b.) For maximum revenue, dR/dp = 0
dR/dp = -20p + 800 = 0
20p = 800
p = 40
Therefore, the maximum revenue will be recorded when the price is set at $40.
Answer:
- Mar 18: 125
- Mar 19: 318
- Mar 20: 743
- Mar 25: 15,070
Step-by-step explanation:
The six seemingly arbitrary points have no common difference or ratio, so cannot be modeled by a linear or exponential function.
The differences of the differences are not constant at any level, so the only polynomial model is 5th-degree. It is ...
(6n^5 -95n^4 +600n^3 -1825n^2 +2814n -1320)/60
where n = days after Mar 11. (Mar 12 corresponds to n=1.) The domain is n ≥ 1.
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The 5th-degree polynomial increases very fast, but not as fast as an exponential function would.
The values for Mar 12 through Mar 25 are ...
3, 8, 11, 16, 25, 50, 125, 318, 743, 1572, 3047, 5492, 9325, 15070
The answer is b why because I had did it on the test and I had got it right HOPEFULLY IT HELPS
We can't answer it I don't think there is enough info
