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3 years ago

HELP ASAP!!!!!!!!!!!!!

Mathematics

1 answer:

Paladinen [302]3 years ago

3 0

Answer:

<h3> A. $\bold{a_n=-3\cdot\left(\frac18\right)^{n-1}}$ </h3>

Step-by-step explanation:

$\begin{cases}a_1=-3\\a_n=a_{n-1}\cdot\dfrac18\end{cases}\\\\\\a_2=a_{2-1}\cdot\frac18=a_1\cdot\frac18\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_1\cdot\frac18}{a_1}=\dfrac18\\\\\\a_n=a_1\cdot r^{n-1}\\\\a_n=-3\cdot\left(\frac18\right)^{n-1}$

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