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Alchen [17]
3 years ago
8

HELP ASAP!!!!!!!!!!!!!

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

<h3>              A.   \bold{a_n=-3\cdot\left(\frac18\right)^{n-1}}</h3>

Step-by-step explanation:

\begin{cases}a_1=-3\\a_n=a_{n-1}\cdot\dfrac18\end{cases}\\\\\\a_2=a_{2-1}\cdot\frac18=a_1\cdot\frac18\\\\r=\dfrac{a_2}{a_1}=\dfrac{a_1\cdot\frac18}{a_1}=\dfrac18\\\\\\a_n=a_1\cdot r^{n-1}\\\\a_n=-3\cdot\left(\frac18\right)^{n-1}

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f(0) = -6

f(2) = 2^2 - 5(2) - 6 = 4 - 10 - 6 = -12

f(2) = -12

f(-1) = -1^2 - 5(-1) - 6 = 1 + 6 - 6 = 1

f(-1) = 1

f(6) = 6^2 -5(6) - 6 = 36 - 30 - 6 = 0

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The second function:

f(x) = x^3 - x^2 - 12

f(0) = 0^3 - 0^2 - 12 = 0 - 0 - 12 = -12

f(0) = -12

f(2) = 2^3 - 2^2 - 12 = 8 - 4 - 12 = -8

f(2) = -8

f(-1) = -1^3 - (-1)^2 - 12 = -1 - 1 - 12 = -14

f(-1) = -14

f(6) = 6^3 - 6^2 - 12 = 216 - 36 - 12 = 168

f(6) = 168

The third function:

f(x) = 5 * 2^x

f(0) = 5 * 2^0 = 5 * 1 = 5

f(0) = 5

f(2) = 5 * 2^2 = 5 * 4 = 20

f(2) = 20

f(-1) = 5 * 2^-1 = 5 * 0.5 = 2.5

f(-1) = 2.5

f(6) = 5 * 2^6 = 5 * 64 = 320

f(6) = 320

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3 years ago
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