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WITCHER [35]
3 years ago
7

The whether the sequence is arithmetic 2,11,20,29,38

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

yes, this sequence is arithmetic

Step-by-step explanation:

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I need help with 14, 15, and 16 please!!
stellarik [79]

Answer:

so 80 plus 20 is a 100

Step-by-step explanation:

thats it

7 0
3 years ago
Math question screen shot down below
ser-zykov [4K]

Answer:

11

Step-by-step explanation:

11,16,12,7,23,9,5,5

arrange to least to greatest

5,5,7,9,11 ,12,16,23

2 middle numbers

11+12= 23

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Median is 11

3 0
3 years ago
Read 2 more answers
Multiply. Write your answer in simplest form.<br><br> 7 x 3/4
sweet-ann [11.9K]
If you would like to calculate 7 * 3/4, you can do this using the following steps:

7 * 3/4 = 21/4 = 5 1/4

The correct result would be 21/4.
8 0
3 years ago
What is the area of the triangle?<br> 9 4 12
LUCKY_DIMON [66]

Answer:

  13.636

Step-by-step explanation:

The area can be found using Heron's formula:

  A = √(s(s-a)(s-b)(s-c))

where s=(a+b+c)/2.

For the given triangle, ...

  a=9, b=4, c=12, s=(9+4+12)/2 = 12.5

  A = √(12.5(3.5)(8.5)(0.5)) = √185.9375 ≈ 13.636

The area of the triangle is about 13.636 square units.

7 0
3 years ago
What is the remainder of (4x2 + 7x-1)= (4 + x)?<br>A. -9x – 1<br>B.23x – 1<br>C.35<br>D.-37​
bearhunter [10]

Answer: I don't know what you meant by remainder but i hope this helps :)

x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}\\

Step-by-step explanation:

\left(4x^2+7x-1\right)=\left(4+x\right)\\\mathrm{Refine}\\4x^2+7x-1=4+x\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\4x^2+7x-1-x=4+x-x\\Simplify\\4x^2+6x-1=4\\\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}\\4x^2+6x-1-4=4-4\\\mathrm{Simplify}\\4x^2+6x-5=0\\\mathrm{For\:}\quad a=4,\:b=6,\:c=-5:\\\quad x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}

\frac{-6+\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\=\frac{-6+\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{2\times \:4}\\=\frac{-6+\sqrt{116}}{8}\\\\Let\: simplify\: ; -6+2\sqrt{29}\\=-2\times \:3+2\sqrt{29}\\=2\left(-3+\sqrt{29}\right)\\=\frac{2\left(-3+\sqrt{29}\right)}{8}\\=\frac{-3+\sqrt{29}}{4}\\

\frac{-6-\sqrt{6^2-4\times \:4\left(-5\right)}}{2\times \:4}\\\\=\frac{-6-\sqrt{6^2+4\times \:4\times \:5}}{2\times \:4}\\\\=\frac{-6-\sqrt{116}}{2\times \:4}\\\\=\frac{-6-2\sqrt{29}}{8}\\\\=-\frac{2\left(3+\sqrt{29}\right)}{8}\\\\=-\frac{3+\sqrt{29}}{4}\\\\\\x=\frac{-3+\sqrt{29}}{4},\:x=-\frac{3+\sqrt{29}}{4}

6 0
3 years ago
Read 2 more answers
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