9514 1404 393
Answer:
21
Step-by-step explanation:
8 years ago, both were 8 years younger, so the total of their ages would have been 68 -2×8 = 52. If the ratio of their ages was 1 : 3, then the son's age then was 1/(1+3) = 1/4 of the total. 1/4×52 = 13.
Now, 8 years later, the son's age is 13 +8 = 21.
__
Then, Aloysius was 3×13 = 39. Now, Aloysius is 39+8 = 47, and the sum of their ages is 21 +47 = 68, as required.
Answer:
34.32%
Step-by-step explanation:
Tom is 45 years old.
Tom earning = $5950 per month
Mortgage payment = $2042
Percentage of amount paid towards mortgage in his income = (2042/5950)*100
= 34.32%
Tom pays 34.32% of his income towards mortgage.
The national average of his age group pays 35% of income towards housing.
Thank you.
Answer:
C.
Step-by-step explanation:
Answer:
15/10
Step-by-step explanation:
Since it is adding you need to get a common denominator(bottom number).
I know that 2 × 5 = 10 so now we multiply 3/5 × 2
we get 6/10
now the problem is 9/10 + 6/10
9 + 6 = 15 and the denominator is 10
15/10
Answer:
Option C
Step-by-step explanation:
You forgot to attach the expression that models the cost of the camping trip during the three days. However, by analyzing the units, the answer can be reached.
The total cost has to be in units of $.
There are two types of costs in the problem:
Those that depend on the number of days ($/day
)
Those that depend on the number of students and the number of days ($/(student * day))
If there are 3 days of camping and b students, then you have to multiply the costs that depend on the days by the number of days (3), and the costs that depend on the number of students you have to multiply them by 'b'
So, if the costs that must be multiplied by 'b' are only those that depend on the number of students, the coefficient of b must be:
3 days (Cost of training + Cost of food Miscellaneous expenses :).
Therefore the correct answer is option C:
C. It is the total cost of 3 days per student of Mr. Brown, with training, food and miscellaneous expenses.
The expression that represents the total expense should have a formula similar to this:
![y = (3 days) *([\frac{20.dollars}{(day * student)} + \frac{30.dollars}{(student * day)} + \frac{50.dollars}{(student * day)}] b + \frac{200}{day}) + 1050.dollars](https://tex.z-dn.net/?f=y%20%3D%20%283%20days%29%20%2A%28%5B%5Cfrac%7B20.dollars%7D%7B%28day%20%2A%20student%29%7D%20%2B%20%5Cfrac%7B30.dollars%7D%7B%28student%20%2A%20day%29%7D%20%2B%20%5Cfrac%7B50.dollars%7D%7B%28student%20%2A%20day%29%7D%5D%20b%20%2B%20%5Cfrac%7B200%7D%7Bday%7D%29%20%2B%201050.dollars)
y = 3 ($ 100b + $ 200) + $ 1050