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kap26 [50]
3 years ago
7

Does the table represent a function? Why or why not?

Mathematics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

Let's put the chart into ordered pairs:

(x, y)

(2,1)

(3,4)

(3,3)

(4,2)

(5,5)

In bold, we see that there are two y-values at x=3. This means that this relation fails the vertical line test (two points on the same verticle line). This is not a function. 

The answer options may be mis-written. 

The answer is no, because one x value corresponds to more than one y-value. 

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If the first three Fibonacci nos. are x1=1, x2=1 and x3=2, what is the least value of n for which xn>60?
olga2289 [7]

Answer:

  11

Step-by-step explanation:

The first 12 terms of the sequence are ...

  1 1 2 3  5 8 13 21  34 55 89 144

The first term that is greater than 60 is the 11th term, 89.

  n = 11

8 0
3 years ago
Find the least common multiple of 12 and 30
Gelneren [198K]
60

12, 24, 36, 48, 60
30, 60 
3 0
3 years ago
Read 2 more answers
Solve the equation 40a^2+4a=0
sergiy2304 [10]
40a^2+4a=0\ \ \ \ |divide\ both\ sides\ by\ 4\\\\10a^2+a=0\\\\a(10a+1)=0\iff a=0\ or\ 10a+1=0\\\\a=0\ or\ 10a=-1\\\\\boxed{a=0\ or\ a=-0.1}
7 0
3 years ago
Please add am explanation.
iren2701 [21]

Answer:

5(k + 1) and 5k + 5

Step-by-step explanation:

The easiest way to do this is to pick any number to substitute in for the variable <em>k </em>for ALL of the expressions, and find the expressions that equal the same as the first expression being compared.

For example, lets just make <em>k </em>equal 1 to make things easy. Plug 1 into <em>k</em> into the first expression. 2k + 2 + k + 3 + 2k → 2(1) + 2 + (1) + 3 + 2(1) = 10.

Now we do the same to the rest of the expressions and see which ones ALSO equal 10.

5(k + 1) → 5(1 + 1) = 10

5k + 5 → 5(1) + 5 = 10

5 + k^5 → 5 + (1)^5 = 6

5k^5 → 5(1)^5 = 5

5 0
2 years ago
5
NeX [460]

Answer:

(b) the answer

Step-by-step explanation:

8 0
2 years ago
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