The complication should the nurse expect is d) pulmonary emboli.
<h3>Why would she develop
pulmonary emboli.?</h3>
The danger that can come up as per postpartum is calf pain with dorsiflexion of the foot and this is usually an indication about deep vein thrombosis.
Hence, having shortness of breath can be linked to pulmonary emboli, since, she had a cesarean birth of twins 6 hours ago .
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A woman who had a cesarean delivery of twins 6 hours ago reports shortness of breath and pain in her right calf. What complication should the nurse expect?
a) fluid volume overload
b) infection
c) hemorrhage
d) pulmonay emboli
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The answer to your question is eligibility for the national merit scholarship program
Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with .
In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:
The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:
Z = -2.3
Z = -2.3 has a p-value of 0.0107.
0.0107 = 1.07% probability that more than 30 are single.
More can be learned about the normal distribution at brainly.com/question/24663213