If the law of demand applies to this good, then Q1 could be:
<h3>What is the law of demand?</h3>
The law of demand refers to the principle that states that the higher the price the lesser the quantity demanded.
So, if the price increases from $10 to $20 then the demand will drop from 100 to 0. If the price reduces, there will be more demand. So, option A is right.
Complete question:
Price: $10, $20
Quantity Demanded: 100, Q1
If the law of demand applies to this good, then Q1 could be
a. 0.
b. 100.
c. 200.
d. 400.
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I think it’s D, please don’t be mad if it’s wrong
Here are 5 advantages of buying a car: Paying less over the long term. Monthly lease payments are generally less expensive than monthly car loan payments. However, with each loan payment, you can build up equity for the future when you decide to sell it or trade it in.
Considering the definition of percentage by mass, the sample of pure lithium nitrate contains 7.99% lithium by mass.
<h3>Definition of percentage by mass</h3>
The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

<h3>This case</h3>
Because percent by mass indicates the ratio of solute to solution based on mass, if the sample has twice the mass of the first sample, the ratio remains constant.
So the percentage by mass is the same.
That is, the sample of pure lithium nitrate contains 7.99% lithium by mass.
.
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The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.
<h3>How to determine the mole of NaHCO₃</h3>
- Molarity of NaHCO₃ = 2 M
- Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
- Mole of NaHCO₃ =?
Mole = Molarity x Volume
Mole of NaHCO₃ = 2 × 0.0316
Mole of NaHCO₃ = 0.0632 mole
<h3>How to determine the mole of CO₂</h3>
NaHCO₃ + HCl —> CO₂ + H₂O + NaCl
From the balanced equation above,
1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.
Thus, 0.0632 mole of CO₂ was obtained from the reaction
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