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bekas [8.4K]
3 years ago
7

What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

Mathematics
1 answer:
yaroslaw [1]3 years ago
4 0

The remainder when the polynomial f(x) = 3x³ - 4x² + 2x + 8 is divided by (x - 5) is constant an equal f(5).

Substitute x = 5 to the polynomial:

f(5)=3(5^3)-4(5^2)+2(5)+8=3(125)-4(25)+10+8\\\\=375-100+18=275+18=293

Answer: (3x³ - 4x² + 2x + 8) : (x - 5) = q(x) + 293.

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In triangle ABC, it is given that A = 70 degree, B = 52 degree, BO and CO are the bisectors of angle B and angle C
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Answer:

Angle OCB= 35 degrees and Angle BOC= 119

Step-by-step explanation:

ANGLE OCB= 1/2 C (Construction of bisector)

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ANGLE OBC= 1/2 B (Construction of bisector)

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180 degree= ANGLE OBC+ANGLE BOC+ANGLE OCB

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180= 61+ANGLE BOC

ANGLE BOC= 180-61

ANGLE BOC= 119

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