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3 years ago

What is -14 squared + 5675843

Mathematics

1 answer:

Hatshy [7]3 years ago

8 0

Answer:

5676039

Step-by-step explanation:

-14² + 5675843

Solve for exponent.

196 + 56758

Add the numbers.

= 5676039

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A circular swimming pool is 21 feet in diameter.What is the circumference of the swimming pool

vazorg [7]

Answer:

65.94 ft.

Step-by-step explanation:

pi*d=C

pi*21=65.94

6 0

3 years ago

I WILL GIVE BRAINLIEST PLEASE HELP!!!

forsale [732]

A. side AB = 38/3 units B.m∠VYX =77°

Step-by-step explanation:

A.A rhombus has its four sides equal. This means side AB=side CD

Given that AB=5x+1 and CD=2x+8 equate the two sides to find value of x as;

5x+1=2x+8

collect like terms

5x-2x=8-1

3x=7

x=7/3

side AB = 5x+1

AB= 5*7/3 +1

AB=35/3 +1

AB=35/3 +3/3 = 38/3

The diagonals of a rhombus intersect to form 90°

Hence

(3n²-0.75)°=90°

3n²=90°+ 0.75°

3n² =90.75° -----dividing by 3 both sides

n² =90.75°/3 =30.25°

n²=30.25°

n=√30.25°

n=5.5°

so angle Z =90°

and angle ZVW =(9n+2)°

∠ZVW = (9*5.5 +2 )° =51.5°

In a rhombus all four sides are equal, thus side VY = YX.This means triangle VYX is an isosceles triangle.

Hence angle ∠YVZ=∠WVZ =51.5°, and because VYX is an isosceles triangle then ∠YXV =51.5° so

∠VYX= 180°-(51.5°+51.5°)

=180°-103°=77°

Learn More

Properties of a Rhombus : brainly.com/question/1305249

Keywords : Rhombus, fraction, simplest form

#LearnwithBrainly

3 0

3 years ago

Maggie's brother is 6 years younger than four times her age. The sum of their ages is 39. How old is Maggie?

poizon [28]

We can set Maggie's age to x

If her brother is six years younger than four times her age, than her brother must be equal to: 4x-6

Since the sum of their ages is 39, we can set up an equation.

(Sum of Maggie's age) + (sum of Maggie's brother's age) = 39

x + (4x -6) = 39

5x -6 = 39

5x = 45

x = 9 , Maggie's age is 9

6 0

3 years ago

Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64

tino4ka555 [31]

$x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}$

By Fermat's little theorem, we have

$x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5$

$x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7$

5 and 7 are both prime, so $\varphi(5)=4$ and $\varphi(7)=6$ . By Euler's theorem, we get

$x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5$

$x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7$

Now we can use the Chinese remainder theorem to solve for $x$ . Start with

$x=2\cdot7+5\cdot6$

Taken mod 5, the second term vanishes and $14\equiv4\pmod5$ . Multiply by the inverse of 4 mod 5 (4), then by 2.

$x=2\cdot7\cdot4\cdot2+5\cdot6$

Taken mod 7, the first term vanishes and $30\equiv2\pmod7$ . Multiply by the inverse of 2 mod 7 (4), then by 6.

$x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6$

$\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}$

$x^5\equiv3\pmod{64}$

We have $\varphi(64)=32$ , so by Euler's theorem,

$x^{32}\equiv1\pmod{64}$

Now, raising both sides of the original congruence to the power of 6 gives

$x^{30}\equiv3^6\equiv729\equiv25\pmod{64}$

Then multiplying both sides by $x^2$ gives

$x^{32}\equiv25x^2\equiv1\pmod{64}$

so that $x^2$ is the inverse of 25 mod 64. To find this inverse, solve for $y$ in $25y\equiv1\pmod{64}$ . Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that $(-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}$ .

So we know

$25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}$

Squaring both sides of this gives

$x^4\equiv1681\equiv17\pmod{64}$

and multiplying both sides by $x$ tells us

$x^5\equiv17x\equiv3\pmod{64}$

Use the Euclidean algorithm to solve for $x$ .

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that $(-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}$ , and so $x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}$

5 0

3 years ago

Joanie wrote a letter that was 1 1/4 pages long. Katie wrote a letter that was 3/4 page shorter than Joanie's letter. How long w

gladu [14]

The answer to your question is 2/4 which is 1/2

8 0

3 years ago