what is the surface area of a square pyramid with base side lengths of 10 inches and a slant height of 14 inches
1 answer:
Answer:
The surface area is
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where

-----> the slant height
substitute the values
![SA=10^{2}+4[\frac{1}{2}(10)(14)]](https://tex.z-dn.net/?f=SA%3D10%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%2814%29%5D)
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I hope this helped!
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