Question

what is the surface area of a square pyramid with base side lengths of 10 inches and a slant height of 14 inches

Answer 1

Answer:

The surface area is $380\ in^{2}$  

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}(b)(l)]$

where

$b=10\ in$

$l=14\ in$ -----> the slant height

substitute the values

$SA=10^{2}+4[\frac{1}{2}(10)(14)]$

$SA=380\ in^{2}$