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andrezito [222]
3 years ago
15

Convert 45.1% to a decimal.​

Mathematics
1 answer:
Dafna11 [192]3 years ago
4 0

Answer:

Queen Messy here!

0.451

moving the decimals to the left when dividing (:

Step-by-step explanation:

You might be interested in
What is the square root of 144?
Novosadov [1.4K]

Answer:

12

Step-by-step explanation:

12 times 12 is 144

Hope this helps

3 0
3 years ago
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days. a. Find the pro
MrMuchimi

Answer:

a. 0.313% (0.003134842261), b. 237.79 days (237.788095878)

Step-by-step explanation:

In this case, the length of pregnancies is a normally distributed variable, with a mean of 266 days, and a standard deviation of 15 days.  

A graph showing the distribution, with regions of interest for the answer, is presented below.

<h3>First Part: Find the probability of a pregnancy lasting 307 days or longer.</h3>

To answer the question regarding <em>the probability of a pregnancy lasting 307 days or longer</em>, it is necessary to calculate what the cumulative probability distribution value is at 307 days. By the way, according to the graph below, 307 days are quite far from the population mean (266 days).

Using the function <em>normaldist(266,15).cdf(307)</em>, from free Desmos software on Internet, we find that, at this length (307 days), the sum of all probabilities for all cases at this value is 99.69%  (0.996865157739).

Considering that the total area of the curve is 1, then <em>the probability of pregnancy lasting 307 days or longer</em> is 1 - 0.996865157739 or 0.003134842261 (or 0.00313), approximately 0.313%, a very low probabilty.

This probability is showed as the "light blue" region at the right extreme of the graph.

<h3>Second Part: Find the length that separates premature babies from those who are not premature.</h3>

To find the length that separates premature babies from those who are not premature, it is a question about <em>find the days related with the probability of 3% (or 0.03)</em> to find such premature babies. So, it is a question of finding a percentile (or 100-quantiles): given the cumulative normal distribution curve, what is the value (length of pregnancies) that represents this 3%.

Using the function <em>quantile(normaldist(266,15), 0.03)</em>, from free Desmos software on Internet, we obtained a value of 237.79 days (237.788095878) for the length of pregnacies of premature babies. In other words, those babies whose mothers have a length of pregnancy <em>lower</em> than 237.79 days are considered premature, or this is "the length that separates premature babies from those who are not premature".

The area below 237.79 days is the blue shaded region in the graph below, at the left extreme of it.

4 0
3 years ago
Read 2 more answers
Can anyone please help me with this question?
dmitriy555 [2]

Answer: y=1.4

1.4 x 85= 119

Step-by-step explanation:

- Do rise over run to get the answer on the graph and finding that Y is 1.4 then multiply to 85 and you will have 119

5 0
3 years ago
Read 2 more answers
A triangle must have one acute angle.
notka56 [123]
This is wrong. a triangle can have 2 or 3 acute angles, only one right angle or one obtuse angle



good luck
8 0
3 years ago
My brother is 5 years older than me. My sister is 3 years younger than me. How old will my sister be when I am n years old?
Arlecino [84]
She will be three years less than whatever age you are
8 0
4 years ago
Read 2 more answers
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