I get a list of zeroes: x<span> = ±</span>1<span>, –3, 2 ... </span>For<span> instance, </span>for x = 2<span> to be a solution</span><span>, then I must have solved the </span>factor<span> equation </span>x – 2<span> = 0, which means that </span>x – 2<span> must have been a ... Find the quadratic with zeroes at </span>x<span> = </span>3<span>/2 and </span>x<span> = </span>–5/<span>4</span>
This the transfer function of a causal
Answer:
x=0
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
5x+2=9x−14x+7−5
5x+2=9x+−14x+7+−5
5x+2=(9x+−14x)+(7+−5)(Combine Like Terms)
5x+2=−5x+2
5x+2=−5x+2
Step 2: Add 5x to both sides.
5x+2+5x=−5x+2+5x
10x+2=2
Step 3: Subtract 2 from both sides.
10x+2−2=2−2
10x=0
Step 4: Divide both sides by 10.
10x/10 = 0/10
Answer:
x=0
Answer:
25
Step-by-step explanation:
60 = 15
100 = x
now cross multiply so 100*15 is 1500 now divide it by 60 which is 25
Simple...
you have: If this cable installer charges $42.50 per hour plus a fixed $45 service charge..then set your equation..using-->>
y=mx+b
How much would the cable installer charge for 5 hours?
y=42.50(5)+45
y=212.50+45
y=$257.50
Thus, your answer.