Question

What is the area of quadrilateral WXYZ?

Answer 1

Answer:

$Area = 105$

Step-by-step explanation:

Given

$W = (-5,4)$ ---- $(x_1,y_1)$

$X = (3,4)$ ------ $(x_2,y_2)$

$Y = (6,-6)$ ----- $(x_3,y_3)$

$Z = (-7,-6)$ ---- $(x_4,y_4)$

Required

Determine the area;

Area is calculated as thus:

$Area = \frac{1}{2}[(x_1.y_2 +x_2.y_3 + x_3.y_4 + x_4.y_1)-(x_2.y_1 +x_3.y_2 + x_4.y_3 + x_1.y_4)]$

Substitute values

$Area = \frac{1}{2}[(-5*4 +3*-6 + 6*-6 + -7*4)-(3*4 +6*4 + -7*-6 + -5*-6)]$

$Area = \frac{1}{2}[(-102)-(108)]$

$Area = \frac{1}{2}[-102-108]$

$Area = \frac{1}{2}[-210]$

$Area = -105$

$Area = 105$

None of the options answer the question: