Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Answer:
Step-by-step explanation:
Area of a square =
If l = ,
Then area =
HOPE THIS HELPS
Answer:
I'm not a hundred percent sure how to answer this one, because you need the height to solve but the other two tick marks would also be twenty because all of the sides are equal to one another.
Answer:
A, g(x) = 7x + 5
Step-by-step explanation:
applying these translations to the parent function f(x) = x, we would get the following equation:
g(x) = 7x + 5
a vertical compression is written before the parent function (in this case f(x)=x), and a shift up is written next to the function. both of these are without parentheses
the answer would be A, g(x) = 7x + 5
Then Alice has a lot of spare time and I need points !!