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4 years ago

6

Help click on the pick for the question

2 answers:

Maksim231197 [3]4 years ago

8 0

The answer is £2.02

insens350 [35]4 years ago

5 0

Answer:

$12.02

$20

-$4.99

-$2.99

=$12.02

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8x-4y=20. What is y simplified?

madam [21]

If you mean trying to figure out what “y” is without the 4. first you have to get the 4y by itself. To do that, subtract 8x from the left side and subtract it from the right side.
-4y=20-8x
Then subtract everything by -4
y=-5+2x
I believe that is the answer (bolded part)

5 0

4 years ago

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Solve each given equation and show your work. Tell whether it has one solution, an infinite number of

hichkok12 [17]

Step-by-step explanation:

a) one solution

x=30

b) no solution 0=0

c) no solution

0≠-21

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3 years ago

PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!!!!!!!!!!!!!!!!!!!PLSSSSSSS HELPPPPPPP I WILL GIVE BRAINLIESTTTTTTTTTT!!!

stira [4]

Answer:

4 $a^{-2}$ $b^{7}$

Step-by-step explanation:

12 a3b5 / 3a5b-2

= (12/3) x (a3 / a5) x (b5/b-2) = 4 $a^{-2}$ $b^{7}$

I hope im right!!

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3 years ago

3. About how much of the earth's surface is deserts?

Murrr4er [49]

Answer:

B- One-Quarter

Step-by-step explanation:

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3 years ago

Find all solutions to the equation. -\dfrac{2}{x(x+2)}=\dfrac{x+3}{x+2}− x(x+2) 2 = x+2 x+3 minus, start fraction, 2, divide

Gnoma [55]

Answer:

$x=-1$

Step-by-step explanation:

We have been given an equation $\frac{-2}{x(x+2)}=\frac{x+3}{x+2}$ . We are asked to find the solutions of our given equation.

First of all, we will cross multiply our given equation as:

$-2(x+2)=x(x+2)(x+3)$

Subtract $x(x+2)(x+3)$ from both sides:

$-2(x+2)-x(x+2)(x+3)=x(x+2)(x+3)-x(x+2)(x+3)$

$-2(x+2)-x(x+2)(x+3)=0$

Now we will factor out $(x+2)$ .

$(x+2)(-2-x(x+3))=0$

$(x+2)(-2-x^2-3x)=0$

$(x+2)(-(x^2+3x+2))=0$

Now we will factor by splitting the middle term.

$-(x+2)(x^2+2x+x+2)=0$

$-(x+2)(x+2)(x+1)=0$

$-(x+2)^2(x+1)=0$

Now we will use zero product property and solve for x as:

$-(x+2)^2=0,(x+1)=0$

$(x+2)=0,(x+1)=0$

$x=-2,x=-1$

Now, we will check for extraneous solutions.

We can see that $x=-2$ will make both denominators zero because our function is not defined at $x=-2$ .

Therefore, the solution for our given equation is $x=-1$ .

7 0

4 years ago

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