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otez555 [7]
3 years ago
12

What is -12/11 = -3/?

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

According to my calculations, the missing number is 11/4

Step-by-step explanation:

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A = lw<br> Whats the description of this formula
antiseptic1488 [7]
The area of a rectangle is its times its width where "A" represents the area, "L" represents the length and "W" represents the width
5 0
4 years ago
Use the number 8,6, and 2 and one operation to write an expression that includes an exponent and has a value of 8. Use each numb
podryga [215]

6 + 2^1 = 8 is the expression that includes an exponent and has a value of 8

<em><u>Solution:</u></em>

Given that, Use the number 8, 6, and 2 and one operation to write an expression that includes an exponent and has a value of 8

We have to use each number only once

Given numbers are 8, 6, 2

Our expression should include exponent and the result should be 8

Among 6 and 2 we can use 2 for exponent

Raise 2 to power of 1

<em><u>The expression becomes:</u></em>

6 + 2^1 = 8

Here we have used one operation, that is addition

Verifying the expression

6 + 2^1 = 6 + 2 = 8

Thus the required expression is found

8 0
4 years ago
The ratio of lollipops to pieces of bubble gum at the party is 2 to 3. There are 24 lollipops. ​ ​What is the total number of lo
disa [49]

Answer: 40

Step-by-step explanation: first make the ratio into a fraction, 2/3

then make 24 into a fraction with the numerator as a variable and the denominator as 24, x/24

then cross multiply 2 and 24.

2x24=48

then divide 48 by 3, 16.

last add the number of lollipops to 16 and the answer is 40.

5 0
3 years ago
Read 2 more answers
Slope = 2; 3-intercept=-1
Zinaida [17]

Answer: Slope = 2; 3-intercept=-1

Step-by-step explanation:

7 0
3 years ago
Please help, I need input on if I did this correctly and you just substitute.
kow [346]

The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

Now multiply the common terms into inside the bracket.

           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

       $=\frac{641}{64}

       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

8 0
3 years ago
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