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uysha [10]
3 years ago
12

Find the solution The graph represents this system of equations.

Mathematics
2 answers:
solong [7]3 years ago
7 0
The solution is the coordinates of the point of intersection 

That is (3 , 1)

Its the last choice.
murzikaleks [220]3 years ago
4 0
For this case we have the following system of equations:
 y = 4 - x

y = x - 2
 We have the graph that represents the solution to the system of equations.
 What you must do for this case, is to observe the point of intersection of both lines.
 At this point, we have the solution to the system of equations.
 The ordered pair solution is:
 (x, y) = (3, 1)

 Answer:
 
The solution to the system of equations is:
 (3, 1)
 option 4
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Yanka [14]
I’m not sure if I get the question, but the second one would be a fact and the others are all statements. I hope this helps :)
5 0
3 years ago
One angle of a right triangle measures 80degrees.what is the measure of the other acute angle
Damm [24]

Answer:

10 degrees

Step-by-step explanation:

1.) every triangle has angles that add up to 180 degrees

2.) a right triangle has a right angle and two acute angles

3.) right=90 degrees; acute=<90 degrees

4.) 90+80=170

5.) 180-170=10

3 0
2 years ago
Read 2 more answers
What is the value of the expression -6 3/4 -1 3/12
hoa [83]

Answer:

-8

Step-by-step explanation:

7 0
2 years ago
The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
jeyben [28]

Answer:

The period of Y increases by a factor of k^ {3/2} with respect to the period of X

Step-by-step explanation:

The equation T ^ 2 = a ^ 3 shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?  

For the planet Y:  

T_y ^ 2 = a_y ^ 3

For planet X:  

T_x ^ 2 = a_x ^ 3

To know the factor of aumeto we compared T_x with T_y

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:  

a_y ^ 3 = (a_xk) ^ 3

So

\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x

Then, the period of Y increases by a factor of k^ {3/2} with respect to the period of X



4 0
3 years ago
Write an equation for the graph.​
lozanna [386]

Answer:

y= 1,000x+55,000

Step-by-step explanation:

55,000 is y intercept. 1,000x is slope.

8 0
3 years ago
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