If you are graphing quadratic equations of the type
ax^2 + bx + c = 0
The equation will look like a "U" <span>if "a" is positive </span>or it will look like an upside-down "U" <span>if "a" is negative </span>
Answer:
(x + 1 s 1) n (x + 12 1)
(x +1<1) n (x + 1 > 1)
Step-by-step explanation:
Just simplify each the statements.
Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.
(x + 1<-1) n (x + 1< 1)
(x <-2) n (x < 0) which is true, so there is a solution.
(x + 1 s 1) n (x + 12 1)
this doesn't make sense so there is no solution.
(x +1<1) n (x + 1 > 1)
(x < 0) n (x > 0)
This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get
3x^2y.
3/6 because there are 6 sides and there are 3 numbers that you want to roll. They are even numbers so if you want to roll half of the numbers but not the other half well you have 3/6
Answer:
-3(r+5)
Step-by-step explanation:
............
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