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Leto [7]
3 years ago
9

angle a and angle C are vertical angles if the measure of angle a equals 3x + 7° and measure of angle C equals x + 53° what is t

he value of x​
Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

x = 23

Step-by-step explanation:

3x + 7 = x + 53 because vertical angles are congruent. So just solve...

3x - x + 7 = x + 53 - x

2x + 7 = 53

2x + 7 - 7 = 53 - 7

2x = 46

x = 23

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find the first six terms of the sequence. a1 = -6, an = 4 • an-1 select one: a. 0, 4, -24, -20, -16, -12 b. -24, -96, -384, -153
MAXImum [283]
If it is a geometric sequence, then ur answer would be d. 
8 0
3 years ago
Let f(x)=3x^2+6x find f(2)<br><br>A.-4<br>B. 0<br>C. 4<br>D. 8
Anon25 [30]

Answer:

B maybe? that doesnt equal any

Step-by-step explanation:

f(x)=3x^2+6x

f(2)=3(2)^2+6(2)

f(2)=3(4)+12

f(2)=12+12

f(2)=24

7 0
4 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
(v+8)(v-3) multiply and simplify the answer
maksim [4K]
V+8*v-3
v+v=2v
8+-3=5
Equation would be: 2v*5 because you cannot combine unlike terms
7 0
3 years ago
Read 2 more answers
11. On a math exam, two students scored 95, five students scored 87,
ivolga24 [154]

Answer:

About 76%.

Step-by-step explanation:

To find the average of numbers, you add all of the numbers together and divide the total by the number of numbers. In this case, your numbers would be 95 twice, 87 five times, 73 three times, 63 four times, and 40 once. The total number of numbers is 15, and the total of all of the exam scores if you add them up is 1136. Finally, you would divide 1136 by 15, which would be 75.7333333, which would be an average of about 76%.

8 0
4 years ago
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