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Leto [7]
3 years ago
9

angle a and angle C are vertical angles if the measure of angle a equals 3x + 7° and measure of angle C equals x + 53° what is t

he value of x​
Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

x = 23

Step-by-step explanation:

3x + 7 = x + 53 because vertical angles are congruent. So just solve...

3x - x + 7 = x + 53 - x

2x + 7 = 53

2x + 7 - 7 = 53 - 7

2x = 46

x = 23

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Financial maths-- multiple choice!!!
Zinaida [17]

Answer:

liquidity

Step-by-step explanation:

when the bank gets only electronic money transfers, they don't get actual money. so, they can use that only for other electronic transfers, but if there is the need for actual money (e.g. a lot of people need a cash payout), the bank is then not able to do that. they don't have enough cash = they are not liquid.

which can actually lead to insolvency.

4 0
3 years ago
Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t
Neporo4naja [7]

Answer:

V=61.66

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

f(x)=g(x)\\ln(x)=\frac{1}{2}x-2

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\

and by replacing in the integral we have

V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\

V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]  

and by evaluating in the limits we have

V=61.66

Hope this helps

regards

3 0
3 years ago
1 -sin^2x÷csc^1x=sinx^2<br>​
Stella [2.4K]

Answer: 37

Step-by-step explanation:

6 0
2 years ago
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
What is the area of 4 10 20
Gnoma [55]
Just multiply the base times height times width which would give you 800
5 0
3 years ago
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