Answer:
Step-by-step explanation:
P = {x : x is a real number between 2 and 7}
{x: 3,4,5,6}
Q = {x : x is all rational number between 2 and 7}
{4 }
We know that P contains all the rational numbers between 2 and 7.
And P ∪ Q and Q ∪ P each of them contain all the real numbers which are between 2 and 7.
{3,4,5,6}
Here Q is the proper subset of P
P ∩ Q = Q ∩ P = Q= {4}
Answer:
x=-37/3
y=-22/3
Step-by-step explanation:
-2x+2y=10 (1)
2x-5y=12 (2)
(1)+(2) <=> -3y=22
Answer:
Step-by-step explanation:
<u>Given the sequence </u>
<u>We see it is an AP with</u>
- The first term a = 13
- Common difference d = 13 ( as 26 - 13 = 39 - 26 = 13)
<u>The 12th term is:</u>
- a₁₂ = a + 11d = 13 + 11*13 = 156
Answer:
G
Step-by-step explanation:
I did this assignment yesterday
