Find the value of x. Will mark brainliest.

The data below are the ages and systolic blood pressures (measured in millimeters of mercury) of 9 randomly selected adults. Age

Ipatiy [6.2K]

Answer:

156

Step-by-step explanation:

Given the data:

Age (X) :

38

41

45

48

51

53

57

61

65

Pressure(Y) :

116

120

123

131

142

145

148

150

152

From the data, we could obtain a regression equation to mod the data Given using a linear regression calculator :

The regression equation obtained is :

y = 1.48769X + 60.46103

Using the model, the predicted blood pressure for a person aged 64 will be :

y = 1.48769(64) + 60.46103

y = 95.21216 + 60.46103

y = 155.67319

y = 156 (nearest whole number)

3 0

2 years ago

Tea costs $4.48 for 8 ounces. What is the cost per one ounce?

olga_2 [115]

Answer:

Question #1 answer is 0.56

7 0

3 years ago

Read 2 more answers

Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha

Nookie1986 [14]

Answer:

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ . The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

$y = a\cdot x^{2}+b\cdot x + c$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$a$ , $b$ , $c$ - Coefficients, dimensionless.

If we know that $(3, -30)$ , $(-2, 0)$ and $(18, 0)$ are part of the parabola, the following linear system of equations is formed:

$9\cdot a +3\cdot b + c = -30$

$4\cdot a -2\cdot b +c = 0$

$324\cdot a +18\cdot b + c = 0$

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

$a = \frac{2}{5}$ , $b = -\frac{32}{5}$ , $c = -\frac{72}{5}$ .

The equation of the parabola is $y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}$ .

Now, we calculate the average rate of change ( $r$ ), dimensionless, between $x = -2$ and $x = 8$ by using the formula of secant line slope:

$r = \frac{y(8)-y(-2)}{8-(-2)}$

$r = \frac{y(8)-y(-2)}{10}$

$x = -2$

$y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}$

$y(-2) = 0$

$x = 8$

$y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}$

$y(8) = -40$

$r = \frac{-40-0}{10}$

$r = -4$

The average rate of change of the parabola is -4.

3 0

3 years ago

Can you please simplify -2x-8x

sergij07 [2.7K]

Answer:

- 10x

Step-by-step explanation:

Step 1:

-2x - 8x

Answer:

- 10x

Hope This Helps :)

4 0

3 years ago

Why are quartiles generally more reliable for judging outliers than mean and standard deviation?

lesya [120]

<span>Quartiles are generally more reliable for judging outliers than mean and standard deviations for 2 reasons. The mean is simply the average of all of the numbers, meaning that an outlier can easily be obscured by the masses. Standard deviation is a better method, however only going over by one standard deviation in either direction would also mask an outlier. A strong outlier however will pull a quartile farther in that direction than would normally be expected.</span>

3 0

3 years ago