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Assoli18 [71]
3 years ago
12

Determine the number of acute, obtuse, and right angles in the shape

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

Answer:

Acute angles measure less than 90 degrees. Right angles measure 90 degrees. Obtuse angles measure more than 90 degrees.

hope it helps

please mark Brainliest

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Mai bought a television for $330. The tax rate is 8%.
erica [24]
1 % of 330 is 3.3 and 3.3x8=26.4 so 26.4+330=356.4
356.4

6 0
3 years ago
I need help
agasfer [191]
(0,4) hope this helps
7 0
3 years ago
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Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 ​ n, equals,
Rom4ik [11]

Answer:

8

Step-by-step explanation:

We are required to evaluate:

0.1m+8-12n

When m=30, n=\frac{1}{4}

Substituting these values into the expression, we have:

0.1m+8-12n=0.1(30)+8-12(\frac{1}{4})\\=3+8-\frac{12}{4}\\=3+8-3\\=8

8 0
3 years ago
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A 17-ft ladder leans against a building so that the angle between the ground and the ladder is 71°. How high does the ladder rea
klasskru [66]

Answer:

there is 16.08 foot high does the ladder reach on the building

Step-by-step explanation:

The computation of the high does the ladder reach on the building is shown below:

Given that

length of the ladder = 17 ft

angle -between the ground and the ladder = 75 degrees

Based on the above information

Here we used the trig-ratio to calculate the same

Sin \theta  = \frac{oppo}{hyp} \\\\Sin 71^{\circ} = \frac{h}{17}

0.946 × 17 = h

The height is 16.08 foot

Hence, there is 16.08 foot high does the ladder reach on the building

6 0
3 years ago
(1−√(5))×(2−√(5)) <br><img src="https://tex.z-dn.net/?f=%281%20%2B%204%20%5Csqrt%7B10%7D%20%29%282%20-%20%20%5Csqrt%7B10%7D%20%2
Leviafan [203]
To simplify these expressions, you can either use a calculator (which I'm assuming your teacher doesn't want you to do) or FOIL (distribute).

The first one would be:

(1- \sqrt{5}) (2- \sqrt{5}) \newline =(1)(2)+(1)(- \sqrt{5} )+(- \sqrt{5})(2)+(- \sqrt{5})(- \sqrt{5}) \newline =2- \sqrt{5}-2 \sqrt{5}+5 \newline =7-3 \sqrt{5}

The second one would be:

(1+4 \sqrt{10})( 2- \sqrt{10}) \newline =(1)(2)+(1)(- \sqrt{10})+(4 \sqrt{10} )(2)  +(4 \sqrt{10})(- \sqrt{10}) \newline =2-\sqrt{10}+8 \sqrt{10} -40 \newline =-38+7 \sqrt{10}
3 0
3 years ago
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