16cm and 12cm
<h3>Δ one fourth of a triangle and a original one is ONLY 16cm and 12cm.</h3><h3 /><h3>multiply 16 by 4 and 12 by 4.</h3><h3 /><h3>add them up and that is ur answer</h3>
-8-3y=25
-8-3y=25+8= 33
-3y=33
-3/-3=33/-3
Y= -11
I think the answer is 7. Hope this helps!
Answer:
A) The areas of both figures are equal.
B) The area of the rectangle is 15 m^2.
Step-by-step explanation:
The area of the rectangle is the product of its length and width:
A = LW = (5 m)(3 m) = 15 m^2
The area of the triangle is half the product of the dimensions of its base and height.
A = (1/2)bh = (1/2)(6 m)(5 m) = 15 m^2
The areas of both figures are 15 m^2.
Answer:
The distance between them changing after 10 minutes will be 9.553 mph.
Step-by-step explanation:
The paths of two runners cross at a stop sign (O). One runner is heading south at a constant rate of 6.5 miles per hour towards A while the other runner is heading west at a constant rate of 7 miles per hour towards B.
So, after 10 minutes the first runner covers a distance of
miles and the second runner covers a distance of
miles.
Therefore, after 10 minutes their distance will be
miles.
Now, the distance between them is given by
AB² = OA² + OB²
Now, differentiating this equation with respect to time t (in hours) we get
![2(AB) \frac{d(AB)}{dt} = 2(OA) \frac{d(OA)}{dt} + 2(OB) \frac{d(OB)}{dt}](https://tex.z-dn.net/?f=2%28AB%29%20%5Cfrac%7Bd%28AB%29%7D%7Bdt%7D%20%3D%202%28OA%29%20%5Cfrac%7Bd%28OA%29%7D%7Bdt%7D%20%2B%202%28OB%29%20%5Cfrac%7Bd%28OB%29%7D%7Bdt%7D)
⇒ ![(AB) \frac{d(AB)}{dt} = (OA) \frac{d(OA)}{dt} + (OB) \frac{d(OB)}{dt}](https://tex.z-dn.net/?f=%28AB%29%20%5Cfrac%7Bd%28AB%29%7D%7Bdt%7D%20%3D%20%28OA%29%20%5Cfrac%7Bd%28OA%29%7D%7Bdt%7D%20%2B%20%28OB%29%20%5Cfrac%7Bd%28OB%29%7D%7Bdt%7D)
⇒ ![1.592 \times \frac{d(AB)}{dt} = 1.083 \times 6.5 + 1.167 \times 7 = 15.208](https://tex.z-dn.net/?f=1.592%20%5Ctimes%20%5Cfrac%7Bd%28AB%29%7D%7Bdt%7D%20%3D%201.083%20%5Ctimes%206.5%20%2B%20%201.167%20%5Ctimes%207%20%3D%2015.208)
⇒
mph.
Therefore, the distance between them changing after 10 minutes will be 9.553 mph. (Answer)