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guajiro [1.7K]
3 years ago
12

Bob and Nina make dog leashes. Bob can make 7 leashes in 2 hours and Nina can make 4 leashes in 1 hour. Enter an equation that c

an be used to find the number of hours, t, it takes Bob and Nina to make 60 leashes together.
Mathematics
1 answer:
Ymorist [56]3 years ago
6 0

The equation that can be used to find the number of hours, t, it takes Bob and Nina to make 60 leashes together is 7.5 t = 60

Step-by-step explanation:

Bob and Nina make dog leashes

  • Bob can make 7 leashes in 2 hours
  • Nina can make 4 leashes in 1 hour

We need to write an equation that can be used to find the number of hours, t, it takes Bob and Nina to make 60 leashes together

∵ Bob can make 7 leashes in 2 hours

∴ The rate of Bob = 7 ÷ 2 = 3.5

∴ Bob can do 3.5 leashes per hour

∵ Nina can make 4 leashes in 1 hours

∴ The rate of Nina = 4 ÷ 1 = 4

∴ Nina can do 4 leashes per hour

∵ They will work together for t hours to make 60 leashes

∵ The number of leashes = Bob's rate × t + Nina's rate × t

∵ Bob's rate = 3.5 leashes/hour

∵ Nina's rate = 4 leashes/hour

∵ The number of leashes = 60

∴ 3.5 t + 4 t = 60

- Add like terms in the left hand sides

∴ 7.5 t = 60

∴ The equation is 7.5 t = 60

The equation that can be used to find the number of hours, t, it takes Bob and Nina to make 60 leashes together is 7.5 t = 60

Learn more:

We can learn more about the equations in brainly.com/question/10689103

#LearnwithBrainly

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VashaNatasha [74]

Answer:

2.5

Step-by-step explanation:

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3 years ago
In the diagram below, BC−→− bisects ∠FBE
nirvana33 [79]

Answer:

<em>m∠EBC = 34° </em>

Step-by-step explanation:

m∠DBC = m∠DBE + m∠ EBC

m∠DBC - m∠DBE = m∠EBC

(12x - 3)° - (5x + 12)° = (3x + 13)°

12x - 5x - 3 - 12 = 3x + 13

4x = 28

x = 7

<em>m∠EBC </em>= (3(7) + 13)° <em>= 34° </em>

7 0
3 years ago
Given g(x)=4x-2/5 find the inverse
docker41 [41]

Answer:

g^-1(x)=1/4x+1/10

Step-by-step explanation:

y=4x-2/5

x=4y-2/5

4y-2/5=x

20y-2=5x

20y=5x+2

y=1/4x+1/10

g^-1(x)=1/4x+1/10

6 0
2 years ago
At what point does the curve have maximum curvature? y = 9 ln(x) (x, y) =
Andrews [41]

y = 9ln(x) 
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2

curvature k = |y''| / (1 + (y')^2)^(3/2) 

<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2) 
= (9/x^2) / (1 + 81/x^2)^(3/2) 
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)] 
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To maximize the curvature, </span>

we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2) 
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2] 
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2) 

Setting k' = 0 yields x = ±9/√2. 

Since k' < 0 for x < -9/√2 and k' > 0 for x > -9/√2 (and less than 9/√2), 
we have a minimum at x = -9/√2. 

Since k' > 0 for x < 9/√2 (and greater than 9/√2) and k' < 0 for x > 9/√2, 
we have a maximum at x = 9/√2. </span>

x=9/√2=6.36

<span>y=9 ln(x)=9ln(6.36)=16.66</span>  

the answer is
(x,y)=(6.36,16.66)
7 0
4 years ago
At a certain college, 28% of the students major in engineering, 18% play club sports, and 8% both major in engineering and play
Alex

Answers: 0.286

Explanation:

Let E → major in Engineering

Let S → Play club sports

P (E) = 28% = 0.28

P (S) = 18% = 0.18

P (E ∩ S ) = 8% = 0.08

Probability of student plays club sports given majoring in engineering,

P ( S | E ) = P (E ∩ S ) ÷ P (E) = 0.08 ÷ 0.28 = 0.286

8 0
3 years ago
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