The answer to the question

Second Roll First Roll 1 2 3 4 5 6 1 1-1 1-2 1-3 1-4 1-5 1-6 2 2-1 2-2 2-3 2-4 2-5 2-6 3 3-1 3-2 3-3 3-4 3-5 3-6 4 4-1 4-2 4-3 4

trapecia [35]

Answer:

what the flip

Step-by-step explanation:

uh

i.d.k..............

i hope this was free pts cuz uhm... i have no idea

3 0

3 years ago

Read 2 more answers

Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3

tamaranim1 [39]

The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-

5(2y^2) - 4(x)
------------------
6x^2y^3

= 2( 5y^2 - 2x)
-----------------
6x^2y^3

= 5y^2 - 2x
-----------
3x^2y^3

5 0

4 years ago

HELP NOW!!!!

VMariaS [17]

Using the concept of probability and the arrangements formula, there is a

0.002 = 0.2% probability that the first 8 people in line are teachers.

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A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which they are positioned is important, and all people will be positioned, and thus, the arrangements formula is used to find the number of outcomes.

The number of possible arrangements from a set of n elements is given by:

$A_n = n!$

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The desired outcomes are:

First 8 people are teachers, in 8! possible ways.
Last 4 are students, in 4! possible ways.

Thus, $D = 8! \times 4!$

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For the total outcomes, number of arrangements of 12 people, thus:

$T = 12!$

The probability is:

$p = \frac{D}{T} = \frac{8! \times 4!}{12!} = 0.002$

0.002 = 0.2% probability that the first 8 people in line are teachers.

A similar problem is given at brainly.com/question/24650047

7 0

3 years ago

Find f(g(x)) and g(f(x)) 1. F(x) = X²-3x+1 g(x)=5x-7

Mariana [72]

We are given the following functions

$\begin{gathered} f(x)=x^2-3x+1 \\ g(x)=5x-7 \end{gathered}$

Let us first find f(g(x)

Substitute x = 5x - 1 into the function f(x) and simplify

$\begin{gathered} f(g(x))=(5x-7)^2-3(5x-7)+1 \\ f(g(x))=(25x^2-2\cdot5x\cdot7+49)^{}-15x+21+1 \\ f(g(x))=25x^2-70x+49^{}-15x+22 \\ f(g(x))=25x^2-70x-15x+49+22 \\ f(g(x))=25x^2-85x+71 \end{gathered}$

Now let us find g(f(x))

Substitute x = x² - 3x + 1 into the function g(x) and simplify

$\begin{gathered} g(f(x))=5(x^2-3x+1)-7 \\ g(f(x))=5x^2-15x+5-7 \\ g(f(x))=5x^2-15x-2 \end{gathered}$

Therefore, f(g(x) and g(f(x)) are

$\begin{gathered} f(g(x))=25x^2-85x+71 \\ g(f(x))=5x^2-15x-2 \end{gathered}$

5 0

1 year ago

What are the subjects you need to study for mid-terms? All of them or just the core subjects? :(

g100num [7]

Well it depends... most of your core classes will have mid terms... but some of you electives/ not core classes have mid terms to

it depends on the teacher... so ask the teachers... and whatever classes have midterms then you need to study for those classes

5 0

3 years ago