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3 years ago

HELP NOW!!!!

1 answer:

7 0

Using the concept of probability and the arrangements formula, there is a

0.002 = 0.2% probability that the first 8 people in line are teachers.

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A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which they are positioned is important, and all people will be positioned, and thus, the arrangements formula is used to find the number of outcomes.

The number of possible arrangements from a set of n elements is given by:

$A_n = n!$

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The desired outcomes are:

Thus, $D = 8! \times 4!$

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For the total outcomes, number of arrangements of 12 people, thus:

$T = 12!$

The probability is:

$p = \frac{D}{T} = \frac{8! \times 4!}{12!} = 0.002$

0.002 = 0.2% probability that the first 8 people in line are teachers.

A similar problem is given at brainly.com/question/24650047

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kap26 [50]

Answer:

y=-4, x=1

Step-by-step explanation:

2x-y=6 x+y=-3

2(-3-y)-y=6 x=-3-y

-6-2y-y=6 x=-3+4

-3y=12 x=1

y=-4

8 0

3 years ago

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

So, for example, if we want an equation whose roots are 4 and -2, we have:

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$