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NISA [10]
3 years ago
13

2x+3y=11 Solve for x and y

Mathematics
1 answer:
irga5000 [103]3 years ago
6 0
To solve this equation you have to isolate one variable, first we will solving for x, then for y.

Solving for x

2x+3y=11

2x=11-3y

\boxed{\boxed{x=\frac{11}{2}-\frac{3}{2}*y}}

Solving for y

2x+3y=11

3y=11-2x

\boxed{\boxed{y=\frac{11}{3}-\frac{2}{3}*x}}
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Find the value of x for which the function y = x5-x³ + x² - 1 has a local minimum.
melisa1 [442]

The given function presents a local minimum in the coordinates (0,-1).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

For solving this question, the given equation should be rewritten  from the factoring.

x^5-x^3+x^2-1=\left(x+1\right)^2\left(x-1\right)\left(x^2-x+1\right)=0. Then, you have 3 equations.

From the Zero Factor Principle, you can write

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Equation 2

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Equation 3

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x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\ \\ x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{3}i}{2\cdot \:1}

From these points it is possible to plot a graph and you can see that the local minimum presents the coordinates (0,-1).

Read more about the factoring here:

brainly.com/question/11579257

#SPJ1

7 0
2 years ago
How do i factor -3s^2-s+10
Lady_Fox [76]
<span>-3s^2-s+10
= (3x - 5)(-x - 2)

hope that helps</span>
7 0
3 years ago
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